计算文件行数的其他方法

Question

我试图在查找单词的索引时打印行号和字符数。有人可以建议一种在 for 循环中不使用 enumerate 的情况下枚举行的替代方法吗？

def find_word(f, word):
    g_indx = 0
    for line_num, line in enumerate(f, start=1):
        indx = 0 
        while (indx != -1):
            indx = line.find(word, indx)
            if indx > -1:
                yield g_indx + indx
                indx += 1
        print(f'Line number {line_num}, characters amount = {len(line)}')
        g_indx += len(line)

try:
    with open("out.txt", encoding="utf-8") as file:
        a = find_word(file, "Hello")
        print(list(a))
except FileNotFoundError:
    print("File cannot be found")
except:
    print("File handling error")

代码正在运行，但我对打印行号的其他方法感兴趣，因为我想避免 enumerate()

Answer 1

只需在循环中自己增加

line_num

变量即可。

def find_word(f, word):
    g_indx = 0
    line_num = 1
    for line in f:
        indx = 0 
        while (indx != -1):
            indx = line.find(word, indx)
            if indx > -1:
                yield g_indx + indx
                indx += 1
        print(f'Line number {line_num}, characters amount = {len(line)}')
        g_indx += len(line)
        line_num += 1