HC-05 连续打印

Question

我正在使用 MIT App Inventor 创建多个电灯开关。每当我从交换机发送文本时，串行监视器都会在不同的行上打印该单词的每个字母。我怎样才能将其更改为整个文本，例如在显示新行文本之前“1on”？

const int led1 = 2;
const int led2 = 3;
const int led3 = 4;

char v = 0;

void setup() {
  Serial.begin(9600);
  pinMode(led1, OUTPUT);
  pinMode(led2, OUTPUT);
  pinMode(led3, OUTPUT);
}

void loop() {
  if (Serial.available() > 0) {
    v = Serial.read();
    Serial.println(v);
    // Serial.print('\n');

    if (v == 'a') {
      digitalWrite(led1, HIGH);
    } else if (v == 'b') {
      digitalWrite(led1, LOW);
    }
    if (v == 'c') {
      digitalWrite(led2, HIGH);
    } else if (v == 'd') {
      digitalWrite(led2, LOW);
    }
    if (v == 'e') {
      digitalWrite(led3, HIGH);
    } else if (v == 'f') {
      digitalWrite(led3, LOW);
    }
  }
}

Answer 1

第 5 行使用 String 或 char 数组，第 16 行使用 readString() 函数读取所有内容。链接

const int led1 = 2;
const int led2 = 3;
const int led3 = 4;

String v = 0; /* use String or char array */

void setup() {
  Serial.begin(9600);
  pinMode(led1, OUTPUT);
  pinMode(led2, OUTPUT);
  pinMode(led3, OUTPUT);
}

  void loop() {
  if (Serial.available() > 0) {
    v = Serial.readString(); /* use readString() function to read all */
    Serial.println(v);
    // Serial.print('\n');

    if (v == "1on") {
      digitalWrite(led1, HIGH);
    } else if (v == "1off") {
      digitalWrite(led1, LOW);
    }
    else if (v == "2on") {
      digitalWrite(led2, HIGH);
    } else if (v == "2off") {
      digitalWrite(led2, LOW);
    }
    else if (v == "3on") {
      digitalWrite(led3, HIGH);
    } else if (v == "3on") {
      digitalWrite(led3, LOW);
    }
  }
}