使用seaborn.color_palette

Question

现在，我的条形在蓝色光谱中颜色（由参数

coolwarm

给出）。例如，我如何更改这两种颜色和它们的顺序之间的分布，例如，将所有条的80％呈红色，而其余的（即20％）为蓝色？ （现在是50-50％的比例）

使用Seaborn或Matplotlib Colormaps没有内置的方式，但这似乎是一种解决方案，可以解决窍门。

import seaborn as sns
import matplotlib.pyplot as plt
import pandas as pd
import numpy as np

## function that generates a color palette
def gen_palette(n_left, n_right, cmap_name="coolwarm", desat=0.999):
    """
    n_left: number of colors from "left half" of the colormap
    n_right: number of colors from the "right half"
    cmap_name: name of the color map to use (ideally one of the diverging palettes)

    return: palette, list of RGB-triples
    """
    palette_1 = sns.color_palette(palette=cmap_name, 
                                  n_colors=2 * n_left, 
                                  desat=desat)[:n_left]
    palette_2 = sns.color_palette(palette=cmap_name, 
                                  n_colors=2 * n_right, 
                                  desat=desat)[n_right:]
    return palette_1 + palette_2

## generate example data
N = 20
rng = np.random.default_rng(seed=42)
y_vals = 10 * rng.random(N)
df = pd.DataFrame(
    {"Col1": np.arange(N),
     "Col2": y_vals}
)

## build the color palette with the desired blue-red split
n_red = round(0.8 * N)
palette = gen_palette(N - n_red, n_red)

## plot
plt.bar(df['Col1'], df['Col2'], 
        width=0.97, 
        color=palette)

Answer 1