当不填写必填字段时，我不希望打开模式框

Question

我的页面上有表单验证。如果某个字段不存在，则模式框不应打开。如果填写了所有必填字段，则打开模型。

我的代码：

<form class="well form-horizontal"   id="contact_form" autocomplete="off">
<fieldset>
<legend><center><h2><b>Registration Form</b></h2></center></legend><br>
<div class="form-group">
  <label class="col-md-4 pd-r control-label">firstname</label>  
  <div class="col-md-4 pd-r inputGroupContainer">
  <div class="input-group">
  <input  name="first_name" id="first_name"  class="form-control tboxs"  type="text">
    </div>
  </div>
</div>

<div class="form-group">
  <label class="col-md-4 pd-r control-label">city</label> 
    <div class="col-md-4 pd-r inputGroupContainer">
    <div class="input-group">
    <input name="city" id="city" placeholder="Solapur" class="form-control tboxs" value="Solapur" type="text" readonly>
    </div>
  </div>
</div>

<div class="form-group">
  <label class="col-md-4 pd-r control-label">village</label> 
    <div class="col-md-4 pd-r inputGroupContainer">
    <div class="input-group">
   <input name="village" id="village" class="form-control tboxs" type="text">
    </div>
  </div>
</div>

<div class="form-group">
  <label class="col-md-4 pd-r control-label"></label>
  <div class="col-md-4 pd-r"><br>
    <button  type="submit" value="submit" class="btn-theme-colored btn" data-toggle="modal" data-target="#exampleModal" data-backdrop="static" data-keyboard="false">SUBMIT <span class="glyphicon glyphicon-send"></span></button>
  </div>
</div>
</fieldset>
</form>

<!-- Modal -->
<div class="modal fade" id="exampleModal" tabindex="-1" role="dialog" aria-labelledby="exampleModalLabel" aria-hidden="true">
  <div class="modal-dialog" role="document">
    <div class="modal-content">
      <div class="modal-header">
        <h5 class="modal-title" id="exampleModalLabel"><font color="black"><strong>Verify OTP</strong></h5>
      </div>
      <div class="modal-body">
 <form method="POST"  id="otp_form" action="">
    <div class="row">
        <div class="col-sm-12 form-group">
            <input type="text" class="form-control tboxs" id="otp_data" name="otp_data" placeholder="Enter OTP" maxlength="4" required="">
        </div>
    </div>
     <div class="row">
        <div class="col-sm-12 form-group">
            <button type="submit" name="verifyotp" class="btn btn-lg btn-info btn-block">Verify</button>
        </div>
    </div>
  </form>
      </div>
    </div>
  </div>
</div>

脚本：

<script>
$("#contact_form").validate(
  {
  rules:{
    "first_name":{
  required: true,
  minlength: 4
  },
  "city":{
  required: true,
  },
  "village":{
  required: true,
  },
  },
messages:{
  "first_name":{
  required: "The name field is mandatory!",
  minlength: "Choose a username of at least 4 letters!",
  },
  "village":{
  required: "The name field is mandatory!",
  },
  "city":{
  required: "The name field is mandatory!",
  },
},

  submitHandler: function(form) {

  $.ajax({
              url: "<?php echo base_url(); ?>MainController/userRegistration",
              type: "post",
              data: $('#contact_form').serialize(),
              dataType:'json',
              }).done(function( data ) {
               console.log(data);
                if(data.status=="true"){
                    alert('Verify Your Otp ');
                    setTimeout(function(){location.reload();},5000);   
                }else{
                    // alert("Try Again");
                }    
        });
    }
  });
</script>

当前，它会打开模式框，而不检查必填字段。如果填写所有必填字段，则打开模式框。请为此提供帮助，我不知道我的代码在哪里错了。

Answer 1

Put required属性应使用的输入。然后在您的JavaScript中：

const form = document.getElementById('contact_form');
if(form.reportValidity()) {
    const formData = $(form).serialize();
}