我最初有一个ng-bootstrap(5.1.4)模态,在我的页面模板中内联打开它的按钮,如下所示:
<ng-template #basicMessage
let-modal>
<div class="modal-header">
<h2 id="modal-basic-title"
class="modal-title">Modal headline</h2>
<button type="button"
class="close"
aria-label="Close"
(click)="modal.dismiss('Close icon clicked')">
<span aria-hidden="true"></span>
</button>
</div>
<div class="modal-body">
<p>Lorem ipsum dolor sit amet, duo ei volumus perfecto ocurreret, nam et volutpat explicari hendrerit.</p>
</div>
</ng-template>
<button class="btn btn-primary mb-3"
(click)="open(basicMessage, { ariaLabelledBy: 'modal-basic-title' })"
matRipple>
View Demo
</button>
此页面上有几个模态演示,每个都有不同的模板标签,例如#singleChoiceActionModal
和#basicMessage
。
现在,我想将每个模式移动到其自己的组件中,并通过viewdemo按钮调用该模式,并传递要打开的演示名称。问题是,一旦将上述模态ng-template移到其自己的组件中,就可以了:
import { Component } from '@angular/core';
@Component({
selector: 'app-ngmodal-basic',
template: `
<ng-template #basicMessage let-modal>
<div class="modal-header">
<h2 id="modal-basic-title" class="modal-title">Modal headline</h2>
<button type="button" class="close" aria-label="Close" (click)="modal.dismiss('Close icon clicked')">
<span aria-hidden="true"></span>
</button>
</div>
<div class="modal-body">
<p>
Lorem ipsum dolor sit amet, duo ei volumus perfecto ocurreret, nam et volutpat explicari hendrerit.
</p>
</div>
</ng-template>
`,
styles: []
})
export class NgmodalBasicComponent {}
然后将该组件添加到我的演示页中,如
<app-ngmodal-basic></app-ngmodal-basic>
<button class="btn btn-primary mb-3"
(click)="open(basicMessage, { ariaLabelledBy: 'modal-basic-title' })"
matRipple>
View Demo
</button>
背景弹出,但没有模式。
由于这有点令人困惑,所以我进行了Stackblitz:https://stackblitz.com/edit/angular-rvsxpz
您必须将模板引用传递给open方法的第一个参数。但是在您的示例中,您传递的是undefined,这就是为什么它不起作用。您必须先获取app-ngmodal-basic模板引用,然后将该引用传递给open方法。要获取app-ngmodal-basic模板参考,请使用ViewChild,然后在app-ngmodal-basic上添加模板变量以获取访问权限