我有一个ShopMicroService,一个CustomerMicroService和一个CartMicroService。
ShopMicroService应该作为API网关工作,并且应该能够控制其他所有服务。它们与Netflix Zuul连接并路由。
我想能够打电话给localhost:8080 / list,并查看来自CustomerMicroService和CartMicroService的数据。但我也无法在ShopController中返回两个方法。我该如何解决这个问题?
Shop2CartConnector:
@FeignClient("cartmicroservice")
public interface Shop2CartConnectorRequester {
@GetMapping("/list")
public List<?> getCart();
Shop2CustomerConnector:
@FeignClient("customermicroservice")
public interface Shop2CustomerConnectorRequester {
@GetMapping("/list")
public List<?> getCustomer();
ShopController:
@ComponentScan
@RestController
public class ShopController {
final Shop2CustomerConnectorRequester shop2CustomerConnectorRequester;
final Shop2CartConnectorRequester shop2CartConnectorRequester;
@Autowired
public ShopController(Shop2CustomerConnectorRequester shop2CustomerConnectorRequester,
Shop2CartConnectorRequester shop2CartConnectorRequester) {
this.shop2CustomerConnectorRequester = shop2CustomerConnectorRequester;
this.shop2CartConnectorRequester = shop2CartConnectorRequester;
}
@GetMapping("/getCustomer")
public List<?> getCustomer() {
return shop2CustomerConnectorRequester.getCustomer();
}
@GetMapping("/getCart")
public List<?> getCart() {
return shop2CartConnectorRequester.getCart();
}
我已经尝试只调用一个方法并使用这两种方法,但它仍然只显示我返回的列表。
基本上,当您进行API调用时,应用程序的request handler
会将传入的HTTPS请求路由到控制器的特定处理程序方法。因此,你不能“返回两种方法”。
但是,如果我理解你正确你想要加入两个列表并将它们返回给客户端 - 如果我错了就纠正我:)为此你可以使用提供Stream API
方法的concat
。例如
@RestController
public class ShopController {
final Shop2CustomerConnectorRequester shop2CustomerConnectorRequester;
final Shop2CartConnectorRequester shop2CartConnectorRequester;
@Autowired
public ShopController(Shop2CustomerConnectorRequester shop2CustomerConnectorRequester,
Shop2CartConnectorRequester shop2CartConnectorRequester) {
this.shop2CustomerConnectorRequester = shop2CustomerConnectorRequester;
this.shop2CartConnectorRequester = shop2CartConnectorRequester;
}
@GetMapping("/listAll")
public List getAllLists() {
List<Customer> customerList = hop2CustomerConnectorRequester.getCustomer();
List<Cart> cartList = hop2CartConnectorRequester.getCart();
List<?> list = Stream.concat(customerList.stream(), cartList.stream()).collect(Collectors.toList());
return list;
}
但我建议使用包装器对象返回两个不同的对象类型,而不是将它们返回到单个列表中。您可能无法从列表中检索哪些对象不属于同一实现(转换等)