Spring安全认证

问题描述 投票:1回答:1

我不能在Spring使用MongoDB使用spring安全性进行身份验证。

实体 :

@Document(collection = "users")
public class Users {

    @Id
    private String id;
    private String username;
    private String email;
    private String password;
    private List<Notification> preferences;


    public Users(String username, String email, String password, List<Notification> preferences) {
        this.username = username;
        this.email = email;
        this.password = password;
        this.preferences = preferences;
    }

    public String getUsername() {
        return username;
    }

    public void setUsername(String username) {
        this.username = username;
    }

    public String getEmail() {
        return email;
    }

    public void setEmail(String email) {
        this.email = email;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }

    public List<Notification> getPreferences() {
        return preferences;
    }

    public void setPreferences(List<Notification> preferences) {
        this.preferences = preferences;
    }
}

服务:

@Component
public class MongoUserDetailsService implements UserDetailsService {

    @Autowired
    private UserRepository repository;

    @Override
    public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
        Users user = repository.findByUsername(username);

        if(user == null) {
            throw new UsernameNotFoundException("User not found");
        }

        List<SimpleGrantedAuthority> authorities = Arrays.asList(new SimpleGrantedAuthority("user"));

        return new User(user.getUsername(), user.getPassword(), authorities);
    }
}

存储库:

import com.example.Start.entities.Users;
import org.springframework.data.mongodb.repository.MongoRepository;
import org.springframework.stereotype.Repository;

@Repository
public interface UserRepository extends MongoRepository<Users, String> {
    Users findByUsername(String username);
}

配置:

    @Configuration
    @EnableConfigurationProperties
    public class SecurityConfiguration extends WebSecurityConfigurerAdapter {

        @Autowired
        MongoUserDetailsService userDetailsService;

        @Override
        protected void configure(HttpSecurity http) throws Exception {
            http
                    .csrf().disable()
                    .authorizeRequests().anyRequest().authenticated()
                    .and().httpBasic()
                    .and().sessionManagement().disable();
        }

        @Bean
        public PasswordEncoder passwordEncoder() {
            return new BCryptPasswordEncoder();
        }

        @Override
        public void configure(AuthenticationManagerBuilder builder) throws Exception {
            builder.userDetailsService(userDetailsService);
        }
    }

当我尝试验证时,它给了我:enter image description here

在我的数据库中,我有这个用户:

{
    "_id" : ObjectId("5b855813d03cce0264de3ab6"),
    "username" : "username",
    "email" : "[email protected]",
    "password" : "123"
}

知道是什么导致了这个吗?

mongodb spring-boot authentication spring-security
1个回答
1
投票

问题是您已将BCryptPasswordEncoder注册为passwordEncoder bean,但您已将密码以明文形式存储在数据库中。现在,在进行身份验证时,它使用BCrypt算法对来自HTTP请求的传入密码进行编码,并将其与明文密码进行比较,该密码显然会失败。这就是为什么你得到“编码密码看起来不像BCrypt”,因为它不是。

简短的修复是编辑你的mongodb用户记录,使用用户名为“username”的用户的密码字段具有以下值,如下所示:

{
    "_id" : ObjectId("5b855813d03cce0264de3ab6"),
    "username" : "username",
    "email" : "[email protected]",
    "password" : "$2a$10$pIUUIHClmGYBnsJzlOHQkeecSwRGAgYlxzRfBFjEqhk6rkQdilTYC"
}

当您使用BCrypt算法对字符串“123”进行编码时,您将获得“$ 2a $ 10 $ pIUUIHClmGYBnsJzlOHQkeecSwRGAgYlxzRfBFjEqhk6rkQdilTYC”。

但正确的修复方法是添加代码来编码密码,然后在应用程序中保存Mongo数据库,如下所示:

@Autowired
private PasswordEncoder passwordEncoder;

public void saveUser(Users user) {
    user.setPassword(passwordEncoder.encoder(user.getPassword()));
    // Save in mongodb
}
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