根据账户类型创建自定义列

Question

我正在尝试使用 SQL 查询构建一个自定义字段，该字段将每个帐户标识为“搜索”或“PMax”或“两者”（搜索和 PMax）。

请帮忙

谢谢你。 桑托什。

这是附图中的原始数据和预期输出。

这是我为实现所需输出而编写的查询，但没有得到正确的结果。

SELECT
         "Testing"."Date" AS 'DATE',
         "Testing"."Account Name" AS 'ACCOUNT',
         "Testing"."Type" AS 'TYPE',
         (
            CASE
                 WHEN "Testing"."Type"  = 'Search'
                 AND    "Testing"."Spend"  > 0
                 AND    "Testing"."Account Name"  IS NOT NULL THEN 'Search'
                 WHEN "Testing"."Type"  = 'Pmax'
                 AND    "Testing"."Spend"  > 0
                 AND    "Testing"."Account Name"  IS NOT NULL THEN 'Pmax'
                 WHEN "Testing"."Type"  = 'Search'
                 AND    "Testing"."Type"  = 'Pmax'
                 AND    "Testing"."Spend"  > 0
                 AND    "Testing"."Account Name"  IS NOT NULL THEN 'Search & Pmax'
                 ELSE 'NA'
             END) AS 'Type_new',
         SUM("Testing"."Spend") AS 'SPEND'
FROM  "Testing" 
GROUP BY "Testing"."Date",
     "Testing"."Account Name",
     "Testing"."Type",
      (
        CASE
             WHEN "Testing"."Type"  = 'Search'
             AND    "Testing"."Spend"  > 0
             AND    "Testing"."Account Name"  IS NOT NULL THEN 'Search'
             WHEN "Testing"."Type"  = 'Pmax'
             AND    "Testing"."Spend"  > 0
             AND    "Testing"."Account Name"  IS NOT NULL THEN 'Pmax'
             WHEN "Testing"."Type"  = 'Search'
             AND    "Testing"."Type"  = 'Pmax'
             AND    "Testing"."Spend"  > 0
             AND    "Testing"."Account Name"  IS NOT NULL THEN 'Search & Pmax'
             ELSE 'NA'
         END) 

Answer 1

您需要使用

GROUP BY

聚合表并计算每组中的结果列。

例如，您可以这样做：

select
  min(date) as date,
  account,
  case when min(account_type) = max(account_type) 
       then min(account_type)
       else concat(max(account_type), ' & ', min(account_type)) as account_type,
  sum(spend) as spend
from t
group by account