例外：无法将具有相同URL和子域的两个Admin（）实例分配给同一应用程序

Question

我正在尝试使用flask-admin限制对管理面板的访问，但出现错误。我也尝试过更改URL名称，但是随后抛出404错误。将flask-admin与ModelView一起使用时，出现以下错误：

异常：无法将具有相同URL和子域的两个Admin（）实例分配给同一应用程序。

app / __ init __。py：

from flask import Flask
from config import Config
from flask_sqlalchemy import SQLAlchemy
from flask_migrate import Migrate
from flask_login import LoginManager
from flask_bootstrap import Bootstrap
from flask_mail import Mail
import logging
from logging.handlers import SMTPHandler, RotatingFileHandler
import os
from flask_admin import Admin, BaseView, expose
from flask_admin.contrib.sqla import ModelView


app = Flask(__name__)
app.static_folder = 'templates/static/'
app.config.from_object(Config)
db = SQLAlchemy(app)
migrate = Migrate(app, db)
login = LoginManager(app)
login.login_view = 'login'
bootstrap = Bootstrap(app)
mail = Mail(app)
admin = Admin(app)


if not app.debug:
    if app.config['MAIL_SERVER']:
        auth = None
        if app.config['MAIL_USERNAME'] or app.config['MAIL_PASSWORD']:
            auth = (app.config['MAIL_USERNAME'], app.config['MAIL_PASSWORD'])
        secure = None
        if app.config['MAIL_USE_TLS']:
            secure = ()
        mail_handler = SMTPHandler(
            mailhost=(app.config['MAIL_SERVER'], app.config['MAIL_PORT']),
            fromaddr='no-reply@' + app.config['MAIL_SERVER'],
            toaddrs=app.config['ADMINS'], subject='Bhavtaal Failure',
            credentials=auth, secure=secure)
        mail_handler.setLevel(logging.ERROR)
        app.logger.addHandler(mail_handler)

    if not os.path.exists('logs'):
        os.mkdir('logs')
    file_handler = RotatingFileHandler('logs/bhavtaal.log', maxBytes=10240,
                                       backupCount=10)
    file_handler.setFormatter(logging.Formatter(
        '%(asctime)s %(levelname)s: %(message)s [in %(pathname)s:%(lineno)d]'))
    file_handler.setLevel(logging.INFO)
    app.logger.addHandler(file_handler)

    app.logger.setLevel(logging.INFO)
    app.logger.info('Bhavtaal startup')


from app import routes, models, errors
from app.models import User
from app.admin import AdminView

admin = Admin(app, name='Home', index_view=AdminView(User, db.session, url='/admin', endpoint='users_'))

app / admin.py：

from flask_admin.contrib.sqla import ModelView
from flask import session, redirect, url_for, request


class AdminView(ModelView):

    def __init__(self, *args, **kwargs):
        super().__init__(*args, **kwargs)
        self.static_folder = 'templates/static/'

    def is_accessible(self):
        return session.get('user') == 'admin'

    def inaccessible_callback(self, name, **kwargs):
        if not self.is_accessible():
            return redirect(url_for('index.html', next=request.url))

Answer 1

我在删除此行后能够解决此问题：

admin = Admin（app）