如何在Zig

Question

搜索时的大多数解决方案返回

std.os.socket

，但是

os

软件包不再定义套接字方法。

const std = @import("std");

pub fn main() !void {
    const addr = try std.net.Address.parseIp("127.0.0.1", 8080);
    const sock_fd = try std.os.socket(std.os.AF.INET, std.os.SOCK.DGRAM, std.os.IPPROTO.UDP);
    defer std.os.close(sock_fd);
    
    try std.os.bind(sock_fd, &addr.any, addr.getOsSockLen());
    
    var buf: [1024]u8 = undefined;
    const len = try std.os.recv(sock, &buf, 0);
    std.debug.print("{s}\n", .{buf[0..len]});
}

Answer 1

i在

Ziggit上找到了答案，在此处将其张贴在此处以获得更好的联系。 thank you thank youdimdim用于解决方案。

const std = @import("std");

pub fn main() !void {
    const sock = try std.posix.socket(std.posix.AF.INET, std.posix.SOCK.DGRAM, std.posix.IPPROTO.UDP);
    defer std.posix.close(sock);

    const addr = try std.net.Address.parseIp("127.0.0.1", 55555);
    try std.posix.bind(sock, &addr.any, addr.getOsSockLen());

    var buf: [1024]u8 = undefined;
    const len = try std.posix.recvfrom(sock, &buf, 0, null, null);
    std.debug.print("recv: {s}\n", .{buf[0..len]});
}

pub fn main（）！void { const addr = try std.net.address.parseip（“ 127.0.0.1”，8080）; const sock_fd = try std.os.socket（std.os.af.inet，std.os.sock.dgram，std.os.ipproto.udp）; defer std.os.close（sock_fd）;

try std.os.bind(sock_fd, &addr.any, addr.getOsSockLen());

var buf: [1024]u8 = undefined;
const len = try std.os.recv(sock, &buf, 0);
std.debug.print("{s}\n", .{buf[0..len]});

Answer 2

}