尝试按一系列数字过滤 SQL 报告

Question

我有一个运行产品销售信息的 SQL 代码，但是我希望它显示一组数字。 ALU 是我的产品编号，我有很大范围的编号，并且只想查看 4000000 到 4009999 之间的 ALU 编号。这是我当前的代码。 我选择了一些要忽略的结果。 任何朝着正确方向的帮助都会很棒。

select 
       --r.sbs_name as "Subsidiary",
       r.store_code as "Store",
       r.ALU as "ALU",
       --r.dcs_code as "DCS Code",
       --r.vend_code as "Vendor Code",
       r.description1 as "Description1",
       --r.attribute as "Attribute",
       --r.item_size as "Size",
       r.qty_sold as "Qty Sold",
       round(
            case when r.ext_cost = 0
                then 0
                else (r.ext_cost / r.qty_sold)
            end, 2) as "Item Cost",
       r.ext_cost as "Total Cost",
       r.ext_price as "Total Retail"
from
(
    select s.sbs_name,
           St.Store_code,
           d.dcs_code,
           v.vend_code,
           i.description1,
           i.attribute,
           i.item_size,
           i.ALU,
           sum(decode(di.item_type, 2, di.qty * -1, di.qty)) as qty_sold,
           sum(round((decode(di.item_type, 2, di.qty * -1, di.qty) * (di.cost)), 2)) as ext_cost,
           sum(round((decode(di.item_type, 2, di.qty * -1, di.qty) * (di.price)), 2)) as ext_price
      from rps.document do
     inner join rps.document_item di
        on do.sid = di.doc_sid
     inner join rps.subsidiary s
        on do.sbs_no = s.sbs_no
       and di.sbs_no = s.sbs_no
     inner join rps.dcs d
        on s.sid = d.sbs_sid
       and di.dcs_code = d.dcs_code
     inner join rps.store st
        on do.store_sid = st.sid
     inner join rps.invn_sbs_item i
        on di.invn_sbs_item_sid = i.sid
       and s.sid = i.sbs_sid
     inner join rps.vendor v
        on i.vend_sid = v.sid
     where do.receipt_type in (0, 1)
       and di.item_type in (1, 2)
       and do.status = 4
       and =-=do.sbs_no=-=
       and =-=st.store_no=-=
       and =-=st.store_code=-=
       and =-=trunc(do.created_datetime)=-=
    group by s.sbs_name,
           St.Store_code,
           d.dcs_code,
           v.vend_code,
           i.description1,
           i.attribute,
           i.item_size,
           i.ALU
) r     

尝试添加 4000000 到 4009999 之间的值，但不确定命令或位置是否正确

Answer 1

其中任何一个都应该有效：

    select 
           <your select clause>
    from
    (
        select <your select clause>
               sum(..)
          from <your from clause>
         where <your where clause)
            AND i.ALU between 4000000 and 4009999
        group by <your group by clause>
    ) r     


    select 
           <your select clause>
    from
    (
        select <your select clause>
               sum(..)
          from <your from clause>
         where <your where clause)
        group by <your group by clause>
    ) r     
    where r.ALU between 4000000 and 4009999