anaconda 环境中 openpyxl 的 Badzipfile 错误

问题描述 投票:0回答:0

你好,我是 python 的新手,正在尝试学习它,我使用 openpyxl 包编写了一个小代码来自动执行 excel 上的任务,并且正在使用一个小电子表格“transactions.xlsx”,但是当我尝试阅读时出现错误床单。请帮我解决这个问题

这是我的代码如下:

  import openpyxl as xl
    wb= xl.load_workbook('transactions.xlsx')
    sheet = wb ['Sheet1']
    cell = sheet['a1']
    print(cell.value)`

我收到的消息:

PS C:\Users\ryan\helloworld> & C:/Users/ryan/anaconda3/python.exe c:/Users/ryan/helloworld/app.py
Traceback (most recent call last):
  File "c:\Users\ryan\helloworld\app.py", line 2, in <module>
    wb= xl.load_workbook('transactions.xlsx')
  File "C:\Users\ryan\anaconda3\lib\site-packages\openpyxl\reader\excel.py", line 124, in __init_rkbook_
    self.archive = _validate_archive(fn)                                                         _
  File "C:\Users\ryan\anaconda3\lib\site-packages\openpyxl\reader\excel.py", line 96, in _validate_archive                                                                                        e_archive
    archive = ZipFile(filename, 'r')
  File "C:\Users\ryan\anaconda3\lib\zipfile.py", line 1267, in __init__
    self._RealGetContents()
  File "C:\Users\ryan\anaconda3\lib\zipfile.py", line 1334, in _RealGetContents
    raise BadZipFile("File is not a zip file")
zipfile.BadZipFile: File is not a zip file

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