我有一个带搜索功能的自定义管理器,它按排名对返回结果进行排序:
class MyManager(models.Manager):
def search(self, query, fa, fb=None, fc=None, fd=None, qs=None):
if not qs:
qs = self.get_queryset()
try:
if not (1 in [c in query for c in '&|()!*:"']):
query = " & ".join([f"{q}:*" for q in query.split()])
vector = SearchVector(*fa, weight="A", config="english")
if fb:
vector += SearchVector(*fb, weight="B", config="english")
if fc:
vector += SearchVector(*fc, weight="C", config="english")
if fd:
vector += SearchVector(*fd, weight="D", config="english")
query = SearchQuery(query, search_type="raw")
qs = (
qs.annotate(search=vector, rank=SearchRank(vector, query))
.filter(search=query)
.order_by("-rank", "-id")
.distinct("rank", "id")
)
qs.count() # Trigger exception
except (ProgrammingError, UnboundLocalError):
qs = qs.none()
return qs
但是当我尝试搜索相关字段时,它仍然返回重复的结果:
class Case(models.Model):
machine = models.ForeignKey(Machine, on_delete=models.CASCADE)
user = models.ForeignKey(Profile, on_delete=models.SET_NULL)
hashtags = models.CharField(max_length=255)
closed = models.BooleanField(default=False)
objects = MyManager()
class CaseProgress(models.Model):
case = models.ForeignKey(Case, on_delete=models.CASCADE)
desc = models.TextField()
class Profile(models.Model):
user = models.OneToOneField(User, on_delete=models.SET_NULL, null=True)
class CaseListView(ListView):
model = Case
def get_queryset(self):
query = self.request.GET.get("query", None)
show_closed = (
True if self.request.GET.get("show_closed", False) == "true" else False
)
if query:
if not show_closed:
qs = self.model.objects.filter(closed=False)
else:
qs = self.model.objects.all()
fa = (
"id",
"machine__serial_number",
"machine__company__name",
"user__user__first_name",
"user__user__last_name",
)
fb = ("hashtags",)
fc = ("caseprogress__desc",)
qs = self.model.objects.search(
query, fa, fb, fc, qs=qs
)
return qs
现在我运行搜索,查询可以在不同的表中找到,而不是返回两个结果,即使我有
distinct("id")
。这是为什么?我已经阅读了关于这个主题的Django手册,但它似乎不适用于我的情况,因为我没有在相关字段上订购。
您的查询指定了
.distinct("rank", "id")
,它与 .distinct("id")
不同。
前者将获得与两个字段匹配的不同结果,而不是其中一个字段。也就是说,具有相同
id
的行仍然会出现在查询集中,只要它们不具有相同的 rank
。