按顺序添加虚拟列但不返回它

Question

我有一个具有point（postgis）属性的实体。我需要返回按用户坐标和实体点之间的距离排序的该实体的集合。

为此，我添加了一个聚合函数来计算该距离并将其添加到ORDER BY中，但我不想返回它。我只需要实体的返回和对象数组。

没有订单，结果是：

[
  {
    "user": "/api/users/1",
    "id": 1,
    "gender": "MALE",
    "createdAt": "2019-04-05T11:03:03+02:00",
    "updateAt": "2019-04-11T11:34:06+02:00",
    "birthdate": "1991-05-13T08:02:32+02:00",
    "deletedAt": null,
    "town": "Miami"
  },
  {
    "user": "/api/users/3",
    "id": 2,
    "gender": "MALE",
    "createdAt": "2019-04-05T13:59:30+02:00",
    "updateAt": "2019-04-11T10:57:40+02:00",
    "birthdate": "1999-04-05T11:48:46+02:00",
    "deletedAt": null,
    "town": "New York"
  },
  {
    "user": "/api/users/7",
    "id": 3,
    "gender": "MALE",
    "createdAt": "2019-04-11T11:11:03+02:00",
    "updateAt": "2019-04-11T11:11:03+02:00",
    "birthdate": "1991-05-13T08:02:32+02:00",
    "deletedAt": null,
    "town": "New York"
  }
]

当我为ORDER BY距离添加下一个代码时（计算器在用户坐标和点之间）

$queryBuilder
    ->addSelect("ST_Distance(o.point, ST_Point(:longitude,:latitude)) AS distance")
    ->addOrderBy("distance", "ASC")
    ->setParameter("longitude", $longitude)
    ->setParameter("latitude", $latitude)
;

我明白了：

[
  {
    "0": {
        "user": "/api/users/1",
        "id": 1,
        "gender": "MALE",
        "createdAt": "2019-04-05T11:03:03+02:00",
        "updateAt": "2019-04-11T11:34:06+02:00",
        "birthdate": "1991-05-13T08:02:32+02:00",
        "deletedAt": null,
        "town": "Miami"
    },
    "distance": "106496.35623204"
  },
  {
    "0": {
        "user": "/api/users/7",
        "id": 3,
        "gender": "MALE",
        "createdAt": "2019-04-11T11:11:03+02:00",
        "updateAt": "2019-04-11T11:11:03+02:00",
        "birthdate": "1991-05-13T08:02:32+02:00",
        "deletedAt": null,
        "town": "New York"
    },
    "distance": "109073.2944295"
  },
  {
    "0": {
        "user": "/api/users/3",
        "id": 2,
        "gender": "MALE",
        "createdAt": "2019-04-05T13:59:30+02:00",
        "updateAt": "2019-04-11T10:57:40+02:00",
        "birthdate": "1999-04-05T11:48:46+02:00",
        "deletedAt": null,
        "town": "New York"
    },
    "distance": "285892.32591062"
  }
]

我需要的结果看起来像第一个json。可以添加ORDER BY但删除/隐藏距离属性吗？

Answer 1

截至doctrine 2.2, Scalar mappings can now be omitted from DQL result，

使用HIDDEN关键字，以便从结果中省略计算字段：

->addSelect("ST_Distance(o.point, ST_Point(:longitude,:latitude)) AS HIDDEN distance")

DQL select expressions documentation

DQL examples