如何在不使用Java的情况下不打印重复的开关值？

Question

我如何在不打印出完全相同的组合的情况下让控制台打印出1套西装和1个号码？

这是我正在创建的扑克游戏的开始。

import java.util.Scanner;

public class Poker {
    public static void main(String[] args) {
        int Cards_Per_Player= 5;
        int Num_Cards = 5;
        int Num_Players = 5;
        int Num_Attempts = 0;
        String suit = "deck";
        String value = "Ace";
        Scanner input = new Scanner(System.in);
        System.out.println("welcome to the den");
        System.out.println("only 2 to 5 players are allowed in here.");
        System.out.println("How many of you are there?");
        Num_Players = input.nextInt();
        Num_Attempts = 1;
        while(Num_Players < 2 |  Num_Players > 5) {
            if(Num_Players < 2 | Num_Players > 5)
                System.out.println("That is wrong try again.");
            Num_Players = input.nextInt();
            Num_Attempts++;
        }
        System.out.println("alright, we got "+ Num_Players + " Here");
        for(int i=1; i <= Num_Players; i++) {
            System.out.println("Player" + i);
            for (int card = 1; card <= Num_Cards; card++) {
                double s1 = Math.random();
                double v1 = Math.random();
                int Suit = (int)(s1 * 4) + 1;
                int Cards = (int)(v1 * 13);
                switch (Suit)
                {
                    case 1: suit = "Hearts"; break;
                    case 2: suit = "Clubs"; break;
                    case 3: suit = "Spades"; break;
                    case 4: suit = "Diamond"; break;
                }
                switch (Cards)
                {
                    case 1: value = "Ace"; break;
                    case 2: value = "2"; break;
                    case 3: value = "3"; break;
                    case 4: value = "4"; break; 
                    case 5: value = "5"; break;
                    case 6: value = "6"; break;
                    case 7: value = "7"; break;
                    case 8: value = "8"; break;
                    case 9: value = "9"; break;
                    case 10: value = "10"; break;
                    case 11: value = "Jack"; break;
                    case 12: value = "Queen"; break;
                    case 13: value = "King"; break;
                }
                System.out.println(" " + value + " of " + suit + ",");
            }
            System.out.println();
        }
    }
}

Answer 1

如果要确保输出不会重复自身，我建议使用java.util.ArrayList。例如，如果在切换后输入java.util.ArrayList和suit == "Hearts"，则可以执行value == "10"，并且在每次打印卡之前，都可以调用java.util.List <Integer> suitList = new ArrayList<>()。 （当然，您也必须对值进行此操作，最好是使自己的类包含两个变量而不是创建2个数组列表）

潜在的实现：

suitList.add(suit)之前

调用System.out.println(" "+value+" of "+suit+",");，值也相同。

和for循环遍历ArrayList以检查是否已打印同一张卡。

Answer 2

您有很多选择，但是我会使用suitList.add(suit)来跟踪已经看到的卡。您可以使用“西服号码”格式或以Set格式创建Set<String> cards，然后调用Set<Card> cards以查看是否找到了生成的卡。

顺便提一下，Java中的约定是将所有变量以小写字母开头，因为像这样的名称在传统上是为类保留的。