MongoDB 使用 $match 和 $group 聚合和汇总结果

Question

所以我在下面的 MongoDB 文档中列出了一组对象：

data=[
{
  "_id": {
    "$oid": "63f5e2449741a13be769ca16"
  },
  "userId": {
    "$oid": "63f5bf0c0dc9b0c36ff32087"
  },
  "Jumlah": 12600,
  "Batch": "9999999",
  "Material":"2123100085",
  "Expired_Date": "2099-99-99",
  "Gedung": "C",
  "Zona": "STAGING INBOUND",
  "Plant": "K118",
  "Transaction_Status": "verified",
  "Transaction_Date": "2023-02-22",
  "createdAt": 1677058628,
  "updatedAt": 1677058628,
  "__v": 0,
  "From": "INBOUND BONGKAR"
},{
  "_id": {
    "$oid": "63f5e2449741a13be769ca16"
  },
  "userId": {
    "$oid": "63f5bf0c0dc9b0c36ff32087"
  },
  "Material":"2123100085",
  "Jumlah": 600,
  "Batch": "9999999",
  "Expired_Date": "2099-99-99",
  "Gedung": "C",
  "Zona": "STAGING INBOUND",
  "Plant": "K118",
  "Transaction_Status": "verified",
  "Transaction_Date": "2023-02-22",
  "createdAt": 1677058628,
  "updatedAt": 1677058628,
  "__v": 0,
  "From": "INBOUND BONGKAR"
},{
  "_id": {
    "$oid": "63f5e2449741a13be769ca16"
  },
  "userId": {
    "$oid": "63f5bf0c0dc9b0c36ff32087"
  },
  "Jumlah": 12100,
  "Batch": "9999999", 
  "Material":"2123100085",
  "Expired_Date": "2099-99-99",
  "Gedung": "C",
  "Zona": "STAGING INBOUND",
  "Plant": "K118",
  "Transaction_Status": "verified",
  "Transaction_Date": "2023-02-23",
  "createdAt": 1677058628,
  "updatedAt": 1677058628,
  "__v": 0,
  "From": "INBOUND BONGKAR"
}
]

我尝试使用 MongoDB 查询按日期对其进行分组，结果如下：

{
    "status": 200,
    "message": "Success",
    "data": [
        {
            "_id": "2022400045",
            "data": [
                {
                    "x": "2023-02-22",
                    "y": 20400
                },
                {
                    "x": "2023-02-25",
                    "y": 20000
                },
                {
                    "x": "2023-02-25",
                    "y": 9000
                },
                {
                    "x": "2023-02-25",
                    "y": 4000
                },
                {
                    "x": "2023-02-25",
                    "y": 7000
                },
                {
                    "x": "2023-02-25",
                    "y": 3000
                },
                {
                    "x": "2023-02-25",
                    "y": 3000
                }
            ]
        },
]
}

这是我的尝试：

const result = await TransactionIB.aggregate([
        { $match: { Transaction_Date: { $gte: date1, $lte: date2 } } },
        {
          $group: {
            _id: "$Material",
            Material_Description: { $first: "$Material_Description" },
            data: {
              $push: {
                x: "$Transaction_Date",
                y: { $sum: "$Jumlah" },
              },
            },
          },
        },
      ]);

这是一种优化查询的方法，因此预期值不仅按材料分组，而且按日期分组，预期结果如下，或对此有任何帮助吗？：

"data": [
        {
            "_id": "2022400045",
            "data": [
                {
                    "x": "2023-02-22",
                    "y": 20400
                },
                {
                    "x": "2023-02-25",
                    "y": 500000
                },
            ]
        },
]

Answer 1

需要两级组，

• $group

  Material

  和

  Transaction_Date

  并在

  Jumlah

   中得到 

  y

• $group

  仅由

  Material

  构建

  data

  数组

db.collection.aggregate([
  {
    $group: {
      _id: {
        Material: "$Material",
        Transaction_Date: "$Transaction_Date"
      },
      Material_Description: {
        $first: "$Material_Description"
      },
      y: {
        $sum: "$Jumlah"
      }
    }
  },
  {
    $group: {
      _id: "$_id.Material",
      Material_Description: {
        $first: "$Material_Description"
      },
      data: {
        $push: {
          x: "$_id.Transaction_Date",
          y: "$y"
        }
      }
    }
  }
])

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