从日期列中获取从今天起接下来 5 天内的日期[重复]

Question

我有一张表格，上面有去年的日期：

ID  start_date
1   2020-09-06 11:21:00
2   2020-10-12 01:43:00
3   2020-09-07 17:22:00
4   2020-11-23 04:23:00
5   2020-09-09 19:50:00

如果今天是

2020-09-05

我需要获取从今天起接下来 5 天内 start_date +1 年的行。

从示例表中，期望的结果是：

1   2020-09-06 11:21:00 (Because 2020-09-06 +1 year = 2021-09-06 is in within 5 days from today)
3   2020-09-07 17:22:00 (Because 2020-09-07 +1 year = 2021-09-07 is in within 5 days from today)
5   2020-09-09 19:50:00 (Because 2020-09-09 +1 year = 2021-09-09 is in within 5 days from today)

我有这样的疑问：

SELECT ID, start_date 
FROM my_table 
WHERE 
DATE( "start_date +1 year" ) >= NOW()
AND
DATE( "start_date +1 year" ) <= NOW("+5 days")

但是它不起作用。接下来我可以尝试什么？

Answer 1

您可以使用 INTERVAL 来获取您需要的日期

SELECT ID, `start_date`
FROM my_table 
WHERE 
DATE(`start_date` + INTERVAL 1 YEAR)  >= CURDATE()
AND
DATE(`start_date` + INTERVAL 1 YEAR)  <= CURDATE() + INTERVAL 5 DAY

身份证 |开始日期         
-: | :------------------
 1 | 2020-09-06 11:21:00
 3 | 2020-09-07 17:22:00
 5 | 2020-09-09 19:50:00

db<>小提琴这里