如何从 imap.fetch 中删除带有 imap.uid 的邮件

Question

我有一个迭代邮箱的函数：

def iterate_box(imap):
    #[...]
    status, messages = imap.select("INBOX")
    total_messages = int(messages[0])
    N = 10000

    for i in range(total_messages, total_messages - N, -1):
        # Fetch the email message by ID
        res, msg = imap.fetch(str(i), "(RFC822)")

        for response in msg:
            if isinstance(response, tuple):
                msg = email.message_from_bytes(response[1])
                # [...] A few processes 
                is_responded = send_my_email(receivers, subject, message)
                if is_responded:
                    delete_mail(imap,uid)
                else:
                    print("Not responded, I keep the mail")

只有在

is_responded

的情况下我才想删除邮件。我的问题是我必须指定 UID 才能删除邮件：

def delete_email_by_uid(imap, uid):
    
    # Search for emails with the given UID
    result, data = imap.uid("search", None, f"UID {uid}")
    
    if result == "OK":
        email_ids = data[0].split()
        if email_ids:
            # Mark the email for deletion
            mail.uid("store", email_ids[0], "+FLAGS", "\\Deleted")
            
            # Permanently remove the email
            mail.expunge()
            print("Email deleted successfully.")
        else:
            print("No email found with the provided UID.")
    else:
        print("Error searching for email.")
    
    # Logout and close the connection
    mail.logout()

我无法在

iterate_box

函数上迭代 UID。如何将

i

的索引 (

iterate_box

) 与消息的 UID“链接”，以便传递到我的

delete_email_by_uid

函数。 我精确地说，我有义务在

iterate_box

函数中迭代索引。

Answer 1

def delete_email_by_uid(imap, uid):

# Search for emails with the given UID
result, data = imap.uid("search", None, f"UID {uid}")

if result == "OK":
    email_ids =  data[0].split()
    email_ids = [email_id.decode("utf-8") for email_id in email_ids]
    for email_id in email_ids:
        # Follow your programm
        # email_ids is your list of UID
        # email_id is the current selected UID of your programm