有没有一种方法可以在不遇到 CharconversionException 异常的情况下打开 xlsx 文件？

Question

我的应用处理excel文件；但是当打开 xlsx Excel 格式时，它给了我以下错误。有什么我做错了或我遗漏了什么吗？下面是代码和错误堆栈跟踪；我已经将错误的来源追溯到这里：

myExcelBook = new XSSFWorkbook(new FileInputStream(f));
myExcelSheet = ((XSSFWorkbook) myExcelBook).getSheetAt(0);

异常堆栈跟踪：

Caused by: java.io.CharConversionException: Characters larger than 4 bytes are not supported: byte 0x8f implies a length of more than 4 bytes
    at org.apache.xmlbeans.impl.piccolo.xml.UTF8XMLDecoder.decode(UTF8XMLDecoder.java:162)
    at org.apache.xmlbeans.impl.piccolo.xml.XMLStreamReader$FastStreamDecoder.read(XMLStreamReader.java:762)
    at org.apache.xmlbeans.impl.piccolo.xml.XMLStreamReader.read(XMLStreamReader.java:162)
    at org.apache.xmlbeans.impl.piccolo.xml.PiccoloLexer.yy_refill(PiccoloLexer.java:3477)
    at org.apache.xmlbeans.impl.piccolo.xml.PiccoloLexer.yylex(PiccoloLexer.java:3962)
    at org.apache.xmlbeans.impl.piccolo.xml.Piccolo.yylex(Piccolo.java:1290)
    at org.apache.xmlbeans.impl.piccolo.xml.Piccolo.yyparse(Piccolo.java:1400)
    at org.apache.xmlbeans.impl.piccolo.xml.Piccolo.parse(Piccolo.java:714)
    at org.apache.xmlbeans.impl.store.Locale$SaxLoader.load(Locale.java:3479)
    at org.apache.xmlbeans.impl.store.Locale.parseToXmlObject(Locale.java:1277)
    at org.apache.xmlbeans.impl.store.Locale.parseToXmlObject(Locale.java:1264)
    at org.apache.xmlbeans.impl.schema.SchemaTypeLoaderBase.parse(SchemaTypeLoaderBase.java:345)
    at org.openxmlformats.schemas.spreadsheetml.x2006.main.SstDocument$Factory.parse(Unknown Source)
    at org.apache.poi.xssf.model.SharedStringsTable.readFrom(SharedStringsTable.java:119)
    at org.apache.poi.xssf.model.SharedStringsTable.<init>(SharedStringsTable.java:106)
    at java.base/jdk.internal.reflect.DirectConstructorHandleAccessor.newInstance(DirectConstructorHandleAccessor.java:67)
    ... 61 more

我想从 xlsx 文件中获取列数和单元格数据以在我的应用程序中进行处理，但是当我在 JavaFx 应用程序中加载文件时，出现错误并且应用程序冻结。

Answer 1

这里的问题是我使用的是 apache poi 和 XML beans 库的过时版本。通过升级到 apache poi version 5.2.3，org.apache.xmlbeans version 5.1.1 和poi-ooxml 版本 5.2.3 ，我能够打开 xlsx 文件。 此外，我在打开一个较大的 xlsx 文件时遇到了以下错误。 错误：

  Exception in thread "main" org.apache.poi.util.RecordFormatException: Tried to read data but the maximum length for this record type is 100,000,000.
If the file is not corrupt and not large, please open an issue on bugzilla to request 
increasing the maximum allowable size for this record type.
You can set a higher override value with IOUtils.setByteArrayMaxOverride()
    at org.apache.poi.poi/org.apache.poi.util.IOUtils.throwRecordTruncationException(IOUtils.java:607)
    at org.apache.poi.poi/org.apache.poi.util.IOUtils.toByteArray(IOUtils.java:249)
    at org.apache.poi.poi/org.apache.poi.util.IOUtils.toByteArrayWithMaxLength(IOUtils.java:220)
    at org.apache.poi.ooxml/org.apache.poi.openxml4j.util.ZipArchiveFakeEntry.<init>(ZipArchiveFakeEntry.java:81)
    at org.apache.poi.ooxml/org.apache.poi.openxml4j.util.ZipInputStreamZipEntrySource.<init>(ZipInputStreamZipEntrySource.java:98)
    at org.apache.poi.ooxml/org.apache.poi.openxml4j.opc.ZipPackage.<init>(ZipPackage.java:132)
    at org.apache.poi.ooxml/org.apache.poi.openxml4j.opc.OPCPackage.open(OPCPackage.java:319)
    at org.apache.poi.ooxml/org.apache.poi.ooxml.util.PackageHelper.open(PackageHelper.java:59)
    at org.apache.poi.ooxml/org.apache.poi.xssf.usermodel.XSSFWorkbook.<init>(XSSFWorkbook.java:290)
    at org.apache.poi.ooxml/org.apache.poi.xssf.usermodel.XSSFWorkbook.<init>(XSSFWorkbook.java:286)
    at com.example.scrapper/com.example.scrapper.ChangeToCSV.main(ChangeToCSV.java:15)

Process finished with exit code 1

我在声明工作簿和其他变量以打开 xlsx 文件之前使用下面的行修复了错误： IOUtils.setByteArrayMaxOverride(1000000000); 插图在这里：

IOUtils.setByteArrayMaxOverride(1000000000);
try {
     FileInputStream inputStream = new FileInputStream(xlsxFilePath);
     Workbook workbook = new XSSFWorkbook(inputStream);
     Sheet sheet = workbook.getSheetAt(0);
     //The rest of the code