我有一个功能,根据所按下的按钮,它会击中另一个端点。但是,这些端点将具有相同的响应,并返回相似的数据。有没有一种方法可以让事情保持干态,而不是将响应复制并粘贴到其他地方?以下功能供参考。
$scope.getModelRunJson = function (xOrY) {
if(xOrY) {
Runs.getData({id: $scope.runId}).then(
function (response) {
$scope.runData = response.data.data[0].runData;
console.log($scope.modelRunData);
let blob = new Blob([$scope.runData], {type: 'json'});
let downloadLink = angular.element('<a></a>');
downloadLink.attr('href', window.URL.createObjectURL(blob));
downloadLink.attr('download', 'modelRun.json');
downloadLink[0].click();
}
)
}
else {
Audit.getData({id: $scope.runId}).then(
function (response) {
$scope.runData = response.data.data[0].runData;
console.log($scope.runData);
let blob = new Blob([$scope.runData], {type: 'json'});
let downloadLink = angular.element('<a></a>');
downloadLink.attr('href', window.URL.createObjectURL(blob));
downloadLink.attr('download', 'modelRun.json');
downloadLink[0].click();
}
)
}
};
这样的事情。 Runs
和Audit
都实现getData
$scope.getModelRunJson = function(xOrY) {
const xy = (xOrY) ? Runs : Audit;
xy.getData({
id: $scope.runId
}).then(
function(response) {
$scope.runData = response.data.data[0].runData;
console.log($scope.modelRunData);
let blob = new Blob([$scope.runData], {
type: 'json'
});
let downloadLink = angular.element('<a></a>');
downloadLink.attr('href', window.URL.createObjectURL(blob));
downloadLink.attr('download', 'modelRun.json');
downloadLink[0].click();
}
)
};