Selenium 无法将密钥发送到 youtube 搜索框

Question

最近我开始使用 selenium 进行一些工作，并遇到了无法使用以下代码将密钥发送到 youtube 搜索框的问题：

from selenium import webdriver
from selenium.webdriver.chrome.service import Service
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
import time
service = Service(executable_path="chromedriver.exe")
driver = webdriver.Chrome(service=service)
driver.get("https://youtube.com")
WebDriverWait(driver, 10).until(EC.presence_of_element_located((By.CLASS_NAME, "ytd-searchbox")))
input_element = driver.find_element (By.CLASS_NAME,"ytd-searchbox")
input_element.send_keys("some text"+Keys.ENTER)
time.sleep(100)

类的名称应该是正确的，因为当我运行该函数时，搜索框会突出显示：

input_element.click()

终端输出为：

DevTools listening on ws://127.0.0.1:61618/devtools/browser/a9e75182-8834-47ba-9b5d-94dad187f4d4
Traceback (most recent call last):
  File "c:\Users\noahm\Desktop\Vs_Code\programming\creativestuff\login_bot.py", line 13, in <module>
    input_element.send_keys("some text"+Keys.ENTER)
  File "C:\Users\noahm\AppData\Local\Packages\PythonSoftwareFoundation.Python.3.11_qbz5n2kfra8p0\LocalCache\local-packages\Python311\site-packages\selenium\webdriver\remote\webelement.py", line 231, in send_keys
    self._execute(
  File "C:\Users\noahm\AppData\Local\Packages\PythonSoftwareFoundation.Python.3.11_qbz5n2kfra8p0\LocalCache\local-packages\Python311\site-packages\selenium\webdriver\remote\webelement.py", line 395, in _execute
    return self._parent.execute(command, params)
           ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
  File "C:\Users\noahm\AppData\Local\Packages\PythonSoftwareFoundation.Python.3.11_qbz5n2kfra8p0\LocalCache\local-packages\Python311\site-packages\selenium\webdriver\remote\webdriver.py", line 354, in execute
    self.error_handler.check_response(response)
  File "C:\Users\noahm\AppData\Local\Packages\PythonSoftwareFoundation.Python.3.11_qbz5n2kfra8p0\LocalCache\local-packages\Python311\site-packages\selenium\webdriver\remote\errorhandler.py", line 229, in check_response  
    raise exception_class(message, screen, stacktrace)
selenium.common.exceptions.ElementNotInteractableException: Message: element not interactable
  (Session info: chrome=126.0.6478.127)
Stacktrace:
        GetHandleVerifier [0x00007FF6B4ECEEA2+31554]
        (No symbol) [0x00007FF6B4E47ED9]
        (No symbol) [0x00007FF6B4D08559]
        (No symbol) [0x00007FF6B4D51D73]
        (No symbol) [0x00007FF6B4D4FEDB]
        (No symbol) [0x00007FF6B4D7D02A]
        (No symbol) [0x00007FF6B4D4BA76]
        (No symbol) [0x00007FF6B4D7D240]
        (No symbol) [0x00007FF6B4D9C977]
        (No symbol) [0x00007FF6B4D7CDD3]
        (No symbol) [0x00007FF6B4D4A33B]
        (No symbol) [0x00007FF6B4D4AED1]
        GetHandleVerifier [0x00007FF6B51D8B1D+3217341]
        GetHandleVerifier [0x00007FF6B5225AE3+3532675]
        GetHandleVerifier [0x00007FF6B521B0E0+3489152]
        GetHandleVerifier [0x00007FF6B4F7E776+750614]
        (No symbol) [0x00007FF6B4E5375F]
        (No symbol) [0x00007FF6B4E4EB14]
        (No symbol) [0x00007FF6B4E4ECA2]
        (No symbol) [0x00007FF6B4E3E16F]
        BaseThreadInitThunk [0x00007FFA88B1257D+29]
        RtlUserThreadStart [0x00007FFA8954AF28+40]

当我尝试该网站的代码时，出现了相同的输出： 文字

非常感谢您的帮助

Answer 1

看起来至少有 9 个节点随选择器返回

".ytd-searchbox"

。

(using chrome inspector)
> location.href
'https://www.youtube.com/'
> document.querySelector(".ytd-searchbox")
NodeList(9) [form#search-form.style-scope.ytd-searchbox, div#container.style-scope.ytd-searchbox, yt-icon#search-icon.style-scope.ytd-searchbox, input#search.ytd-searchbox, div#search-clear-button.style-scope.ytd-searchbox, ytd-button-renderer.style-scope.ytd-searchbox, button#search-icon-legacy.style-scope.ytd-searchbox, yt-icon.style-scope.ytd-searchbox, tp-yt-paper-tooltip.style-scope.ytd-searchbox]

通常，除非必要，否则使用

class

属性并不是一个好主意。

奇怪的是，就 YouTube 的搜索框而言，“ID”甚至不是唯一的 🤔

尝试在此 CSS 选择器上进行匹配：

...

input_element = driver.find_element (By.CSS_SELECTOR, "input#search")
input_element.send_keys("some text"+Keys.ENTER)

...