如何知道beautifulsoup中Web抓取中的最后一个页码网站?

问题描述 投票:0回答:2

我正在从flipkart抓取数据,我要在其中抓取所有产品的名称,价格和评分。因此,我想从所有页面中抓取所有必需的信息。此链接共有11页:https://www.flipkart.com/mobiles/mi~brand/pr?sid=tyy%2C4io&otracker=nmenu_sub_Electronics_0_Mi因此,如何循环播放直到到达页面末尾,即直到第11页。

python web beautifulsoup scrape
2个回答
1
投票
from bs4 import BeautifulSoup
import requests
from itertools import zip_longest


def mxnum():
    r = requests.get(
        "https://www.flipkart.com/mobiles/mi~brand/pr?sid=tyy%2C4io&otracker=nmenu_sub_Electronics_0_Mi")
    soup = BeautifulSoup(r.text, 'html.parser')
    for item in soup.findAll("div", {'class': '_2zg3yZ'}):
        mxnum = list(item.strings)[0].split(" ")[-1]
    return int(mxnum) + 1


mxnum = mxnum()


def Parse():
    with requests.Session() as req:
        names = []
        prices = []
        rating = []
        for num in range(1, mxnum):
            print(f"Extracting Page# {num}")
            r = req.get(
                f"https://www.flipkart.com/mobiles/mi~brand/pr?sid=tyy%2C4io&otracker=nmenu_sub_Electronics_0_Mi&page={num}")
            soup = BeautifulSoup(r.text, 'html.parser')
            for name in soup.find_all("div", {'class': '_3wU53n'}):
                names.append(name.text)
            for price in soup.find_all("div", {'class': '_1vC4OE _2rQ-NK'}):
                prices.append(price.text[1:])
            for rate in soup.find_all("div", {'class': 'hGSR34'}):
                rating.append(rate.text)
    for a, b, c in zip_longest(names, prices, rating):
        print("Name: {}, Price: {}, Rate: {}".format(a, b, c))


Parse()

0
投票

第1页到第11页的url是由:定义的:

https://www.flipkart.com/mobiles/mi~brand/pr?sid=tyy%2C4io&otracker=nmenu_sub_Electronics_0_Mi&page={n}

    where n is from 1 to 11

因此您可以创建一个n = 1到11的循环,并在循环中将n替换为其当前值。

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