问题读取数据时访问python中的JSON文件， 我已经在Python中导入一个JSON文件，以推断我在其中选择包含不同数据的每个数据或主要数据的信息。当我尝试选择prin时...

Question

AccessLevels

json：

Accesso = df['AccessLevels']
print(Accesso)

打印访问级别的结果是：

"AccessLevels": {
    "Home.btnBuzzer": 0,
    "Home.btnLogin": 0,
    "Home.btnLogout": 0,
    "Home.btnMenu": 0,
    "L2A_ConfEdit.btnRecSave": 2,
    "L2A_ConfEdit.cbNameConf": 4,
    "L2A_ConfEdit.editParameters": 4,
    "L2B_ProgEdit.btnRecActivate": 1,
    "L2B_ProgEdit.btnRecSave": 2,
    "L2B_ProgEdit.btnRecSaveAs": 2,
    "L2B_ProgEdit.cbNameProg": 1,
    "L2B_ProgEdit.editParameters": 2,
    "L2E_Stats.btnRstPar": 1,
    "L2E_Stats.btnRstTot": 2,
    "L2_Menu.btnConfEdit": 0,
    "L2_Menu.btnMaint": 4,
    "L2_Menu.btnProgEdit": 0,
    "L2_Menu.btnRtCmds": 0,
    "L2_Menu.btnStats": 0,
    "L2_Menu.btnTestControl": 2
},

注意JSON文件包含约12K行

Home.btnBuzzer  0.0 
Home.btnLogin   0.0 
Home.btnLogout  0.0 
Home.btnMenu    0.0 
L2A_ConfEdit.btnRecSave  2.0 
  ... 
5    NaN
6    NaN
7    NaN 
8    NaN 
9    NaN
Name: AccessLevels, Length: 74, dtype: float64

import json
import pandas as pd

# Replace 'your_file.json' with the path to your JSON file
with open('00_000000065.json', 'r') as file:
    data = json.load(file)

#print whole json file
#print(data)


df = pd.DataFrame(data)
#Info = df['Info']['CPU12 prog code']
#print(Info)
#print("\nPrint the whole json file as a db to see how it works")    
#print(df)

print("\nPrinting the recipes\n")
#Ricetta = df['Recipes']
#Step = df['Recipes']['Programs']['13']['Step']['007']
#print(f"Print me step {Step}")

Info = df['Info']['CPU12 prog code']
print(Info)

Image = df['zImages']['0']
print(Image)


Step1 = df['Recipes']['Configs']['00']['Step']

print(Step1)

print("\nTest of the various levels\n")
Accesso = df['AccessLevels']
print(Accesso)

print("\nPrint of the counter\n")
Contatore = df['CounterEnabled']
print(Contatore)

问题在JSON中，也就是说，导入AccessLevel时，它包含一个字典（嵌套结构），而PANDAS并不能正确地将JSON弄平，从而导致对值的非直接访问。

要解决它，创建将其转换为两列表的数据框架，将密钥列设置为索引，以便您可以通过键访问该值。