我目前正在使用以下代码将图像上传到ftp服务器:
<input name="userfile" type="file" size="50">
...
$filep=$_FILES['userfile']['tmp_name'];
$name=$_FILES['userfile']['name'];
$upload = ftp_put($conn_id, $paths.'/'.$name, $filep, FTP_BINARY);
除了只上传一张图片,此方法工作正常。
多(3-4)张图片上传的任何帮助。
提前致谢
<input name="userfile[]" type="file" size="50" />
<input name="userfile[]" type="file" size="50" />
<input name="userfile[]" type="file" size="50" />
for($i = 0; $i < count($_FILES['userfile]); $i++) {
$filep=$_FILES['userfile']['tmp_name'][$i];
$name=$_FILES['userfile']['name'][$i];
$upload = ftp_put($conn_id, $paths.'/'.$name, $filep, FTP_BINARY);
}
您应该一张一张地异步上传文件:)
HTML:
<input name="userfile[]" type="file" size="50" />
<input name="userfile[]" type="file" size="50" />
<input name="userfile[]" type="file" size="50" />
PHP的:
for( $i = 0 ; $i < count( $_FILES['userfile'] ) ; $i++ )
{
$filep = $_FILES['userfile']['tmp_name'][$i];
$name = $_FILES['userfile']['name'][$i];
$upload = ftp_put( $conn_id , $paths . '/' . $name , $filep , FTP_BINARY );
}
这是我用过的。 所有图像字段具有files
的相同name
属性值
<input type="file" name="files[]" class="files" multiple />
可用于html5,或为非html5添加此行的倍数。 我将jquery用于上传器,但是您可以看到多个上传字段。
显然,您可以更改我的代码以使用ftp代码,但这也是另一种方法。
$files = array();
$allowed_filetypes = array('.jpg','.jpeg','.gif','.bmp','.png','.tif');
$max_filesize = 1524288;
$upload_path = 'images/image_uploads/';
for ($i = 0; $i < count($_FILES['files']['name']); $i++){
if($_FILES['files']['name'][$i] != "") {
$filename = $_FILES['files']['name'][$i];
$ext = substr($filename, strpos($filename,'.'), strlen($filename)-1);
$ext = strtolower($ext);
if(!in_array($ext,$allowed_filetypes))
die("The file you attempted to upload ($filename) is not allowed.");
if(filesize($_FILES['files']['tmp_name'][$i]) > $max_filesize)
die("The file you attempted to upload ($filename) is too large.");
if(!is_writable($upload_path))
die("You cannot upload to the specified directory, please CHMOD it to 777.");
$ran = rand();
$filename = $ran.$ext;
if(move_uploaded_file($_FILES['files']['tmp_name'][$i],$upload_path.$filename)) {
$result = mysql_query("Insert Into image_uploads_images (upload_id, image, original_name) Values ('$id', '$filename', '".$_FILES['files']['name'][$i]."');");
if($result){
array_push($files, "http://www.site.com/images/image_uploads/$filename => ".$_FILES['files']['name'][$i]);
}else{
echo "<p style=\"color:#cc3333;\">Unable to upload ".$_FILES['files']['name'][$i]."</p>";
}
}else{
echo "<p style=\"color:#cc3333;\">Unable to upload ".$_FILES['files']['name'][$i]."</p>";
}
}
}