如何分配大小由两个向量定义的数组？

Question

我想创建由两个向量定义的大小的零点，这将在 2D 和 3D 中工作。

%% Setting in 2D
% rectangular domain with left bottom corner [_1,_2]
% and right top  corner [_1,_2]

    lb_corner=[-1,-2]
    rt_corner=[2,2]

    domain_size=rt_corner - lb_corner; 

    dim=size(domain_size,2);

    nb_pixels=[5,4]; % number of pixels in [x_1,x_2]

%% Mesh parameters
   pixel_size= domain_size./nb_pixels;

%% Coordinates

    if dim == 2
        x_coords=zeros(nb_pixels(1),nb_pixels(2),dim);
    elseif dim == 3
        x_coords=zeros(nb_pixels(1),nb_pixels(2),nb_pixels(3),dim);

    end

我想用类似的东西替换 if 条件：

%    x_coords=zeros(nb_pixels,dim); 

这应该在二维中创建大小为

(nb_pixels(1),nb_pixels(2),dim)

的数组， 和 3D

 中大小为 

(nb_pixels(1),nb_pixels(2),nb_pixels(3),dim)

的数组

Answer 1

将

nb_pixels

更改为元胞数组并使用

{:}

将其元素作为逗号分隔列表获取：

dim = 2;
nb_pixels = {5, 4};
x_coords=zeros(nb_pixels{:}, dim)
x_coords =

ans(:,:,1) =

   0   0   0   0
   0   0   0   0
   0   0   0   0
   0   0   0   0
   0   0   0   0

ans(:,:,2) =

   0   0   0   0
   0   0   0   0
   0   0   0   0
   0   0   0   0
   0   0   0   0

dim = 2;
nb_pixels = {5, 4, 2};
x_coords=zeros(nb_pixels{:}, dim)
x_coords =

ans(:,:,1,1) =

   0   0   0   0
   0   0   0   0
   0   0   0   0
   0   0   0   0
   0   0   0   0

ans(:,:,2,1) =

   0   0   0   0
   0   0   0   0
   0   0   0   0
   0   0   0   0
   0   0   0   0

ans(:,:,1,2) =

   0   0   0   0
   0   0   0   0
   0   0   0   0
   0   0   0   0
   0   0   0   0

ans(:,:,2,2) =

   0   0   0   0
   0   0   0   0
   0   0   0   0
   0   0   0   0
   0   0   0   0