javax.servlet.ServletException：javax.crypto.IllegalBlockSizeException：使用填充密码解密时，输入长度必须是 16 的倍数

Question

如何解决以下问题。

action.java

:

byte[] decValue = c.doFinal(decordedValue);
account_bean fromBean = (account_bean) form;
String account_name = fromBean.getName();
String encrypted_password = fromBean.getPassword();
String account_password = AESencrp.decrypt(encrypted_password.toString().trim());

AESencrp.java

:

import java.security.*;
import javax.crypto.*;
import javax.crypto.spec.SecretKeySpec;
import sun.misc.*;
public class AESencrp 
{
 private static final String ALGO = "AES";
private static final byte[] keyValue = 
    new byte[] { 'T', 'h', 'e', 'B', 'e', 's', 't',
 'S', 'e', 'c', 'r','e', 't', 'K', 'e', 'y' };
 public static String encrypt(String Data) throws Exception 
 {
    Key key = generateKey();
    Cipher c = Cipher.getInstance(ALGO);
    c.init(Cipher.ENCRYPT_MODE, key);
    byte[] encVal = c.doFinal(Data.getBytes());
    String encryptedValue = new BASE64Encoder().encode(encVal);
    return encryptedValue.toString().trim();
 }
 public static String decrypt(String encryptedData) throws Exception 
 {
    Key key = generateKey();
    Cipher c = Cipher.getInstance(ALGO);
    c.init(Cipher.DECRYPT_MODE, key);
    byte[] decordedValue = new BASE64Decoder().decodeBuffer(encryptedData);
    byte[] decValue = c.doFinal(decordedValue);
    String decryptedValue = new String(decValue);
    return decryptedValue.toString().trim();
 }   
 private static Key generateKey() throws Exception 
 {
    Key key = new SecretKeySpec(keyValue, ALGO);
    return key;
 }
 }

错误：

javax.servlet.ServletException: javax.crypto.IllegalBlockSizeException: Input length must be multiple of 16 when decrypting with padded cipher

javax.crypto.IllegalBlockSizeException: Input length must be multiple of 16 when decrypting with padded cipher

Apache Tomcat/7.0.27

Answer 1

使用

UTF8

字符集对字符串进行编码/解码。

编码

Data.getBytes("UTF8")  

解码

new String(decValue, "UTF8")