生成 PHP 范围内的随机浮点数

问题描述 投票:0回答:4

我有一个通过以下代码初始化骰子对象的代码:

public function initializeDiceSides($totalSides, $fair, $maxProbability = 100) {
   $maxTemp = $maxProbability;
   $sides = array();

   for ($side = 0; $side < $totalSides; $side++) {
     //if we want fair dice just generate same probabilities for each side
     if ($fair === true) {
       $probability = number_format($maxProbability/$totalSides, 5);
     } else {
       //set probability to random number between 1 and half of $maxTemp
       $probability = number_format(mt_rand(1, $maxTemp/2), 5);

       //subtract probability of current side from maxtemp
       $maxTemp= $maxTemp- $probability;

       $sides[$side] = $probability;
     }
   }

   echo $total . '<br />';
   print_r($sides);
}

上面的代码打印:

89
Array ( [0] => 48.00000 [1] => 13.00000 [2] => 14.00000 
        [3] => 9.00000 [4] => 2.00000 [5] => 2.00000 )

我希望能够生成浮点数而不是整数,我想要类似的东西

Array ( [0] => 48.051212 [1] => 13.661212 [2] => 14.00031 
        [3] => 9.156212 [4] => 2.061512 [5] => 2.00000 )
php random
4个回答
10
投票

一个简单的方法是使用

lcg_value
并乘以范围并添加最小值

function random_float ($min,$max) {
    return ($min + lcg_value()*(abs($max - $min)));
}

2
投票

我只是生成 0 到 999999 之间的随机数,然后将它们除以 100000


1
投票

您可以将输入到

mt_random
的变量乘以一个系数,例如 100000,然后将输出除以相同的系数以获得浮点值。


1
投票
function random_float($min = 0, $max = 1, $includeMax = false) {
    return $min + \mt_rand(0, (\mt_getrandmax() - ($includeMax ? 0 : 1))) / \mt_getrandmax() * ($max - $min);
}
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