左JOIN的最新记录

问题描述 投票:0回答:3
想象我在sqlserver中有以下3个表:

Customer (CustomerID, FirstName, LastName) Address (AddressID, CustomerID, Line1, City, State) Product (ProductID, CustomerID, Description)
客户可以有多个送货地址和Mulitple产品。

我想做的是列出每个州由最新地址记录确定的每个州的客户数量。 例如“最后有多少客户在每个州收到产品?”。 因此,我对客户的任何以前的地址记录都不感兴趣,仅是最近的(由地址ID确定)。

State | Number of Customers -------------------------- CA | 32 GA | 12 TX | 0 OH | 18

我通常会做类似的事情:

SELECT a.State, count(c.CustomerID)
FROM Product p
INNER JOIN Customer c ON c.CustomerID = p.CustomerID
LEFT JOIN Address a ON a.CustomerID = c.CustomerID
WHERE p.ProductID = 101
GROUP BY a.State

否,因为客户可能只有多个地址,只有在最近的地址记录的状态下才能计算客户?

P.S。以上是一个纯粹的示例场景,可以轻松解释我要实现的连接,并且无法反映实际的系统设计。
    

trone this:

SELECT a.State, count(c.CustomerID) FROM Product p INNER JOIN Customer c ON c.CustomerID = p.CustomerID LEFT JOIN Address a ON a.CustomerID = c.CustomerID AND a.AddressID = ( SELECT MAX(AddressID) FROM Address z WHERE z.CustomerID = a.CustomerID ) WHERE p.ProductID = 101 GROUP BY a.State
sql sql-server sql-server-2005
3个回答
169
投票

您也可以尝试(假设我记得我的SQLServer语法正确):

SELECT state, count(customer_id)
FROM (
    SELECT
        p.customer_id
        , (SELECT TOP 1 State FROM Address WHERE Address.CustomerID = p.CustomerID ORDER BY Address.ID DESC) state
    FROM Product p
    WHERE p.ProductID = 101)
GROUP BY state

3
投票

我看不到如何在没有订单和订购表中执行此操作。订单表将包括CustomerId Spiepting Date和ShiptoAddressid,OrderDetails将具有OrderID和Productid。然后,您需要一个嵌套查询来确定最新订单(以及最新的地址),将其加入订单详细信息以获取订购产品,然后过滤您关心的产品。

SELECT *
FROM parent p
JOIN child c ON p.parent_id = c.parent_id
WHERE c.child_id = (
    SELECT child_id
    FROM child
    WHERE parent_id = p.parent_id
    ORDER BY created_at DESC
    LIMIT 1
);

2
投票

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