如何在 Python 上的 Playwright 中获取特定 cookie？

Question

import asyncio
import re

from playwright.async_api import async_playwright, Playwright, expect


async def geochange(playwright: Playwright):
    chromium = playwright.chromium
    browser = await chromium.launch()
    context = await browser.new_context()
    page = await context.new_page()
    await page.goto("https://google.com")
    await page.locator(".popup__close").click()
    geo_cookies = await page.context.cookies()
    print(geo_cookies)

我有代码块，我需要获取特定的cookie，但不知道我需要在await page.context.cookies()处的url中放入什么。

当我运行这个块时，我得到完整的cookie，但我只需要这部分的“lim”：

{'name': 'siteCityCode', 'value': 'lim'....

Answer 1

要从

page.context.cookies()

返回的 cookie 列表中获取特定 cookie，您可以根据名称过滤 cookie。由于您只需要名称为

siteCityCode

的 cookie，因此您可以使用简单的列表理解或循环来提取它。

这是您修改后的代码来实现此目的：

import asyncio
import re
from playwright.async_api import async_playwright, Playwright, expect

async def geochange(playwright: Playwright):
    chromium = playwright.chromium
    browser = await chromium.launch()
    context = await browser.new_context()
    page = await context.new_page()
    await page.goto("https://google.com")
    await page.locator(".popup__close").click()
    geo_cookies = await page.context.cookies()

    # Extract the specific cookie 'siteCityCode'
    site_city_code_cookie = next((cookie for cookie in geo_cookies if cookie['name'] == 'siteCityCode'), None)
    
    if site_city_code_cookie:
        print(site_city_code_cookie['value'])
    else:
        print("Cookie 'siteCityCode' not found")

    await browser.close()

async def main():
    async with async_playwright() as playwright:
        await geochange(playwright)

asyncio.run(main())

在此代码中：

1. geo_cookies

   变量保存由

   page.context.cookies()

   检索到的所有cookie。
2. 我们在

   next()

   函数中使用生成器表达式来查找名为

   siteCityCode

   的 cookie。
3. 如果找到cookie，则打印其值；否则，打印一条消息，指示未找到 cookie。

这种方法可确保您只获得您感兴趣的特定 cookie。