两个函数相互调用，完成后发送消息

Question

我有两个相互调用的函数。如何在满足所有条件时发送消息？

我的代码：

const func1 = async (arg) => {
  let table_id = result.data.internal_id;
  const response = await axios_Func({ graphQL query });
  console.log(`${response.data.name} - ${table_id}`);
  return func2({ query: graphQL_query, table_id });
}

func2 = async (result, table_id) => {
  let dev = await getAllTables({ query: tables(123) });
  let prod = await getAllTables({ query: tables(321) });
  let prod_id = new Set();
  result.data.data.table.table_fields.forEach((d) => {
    if (d. connector != null && !(d.name in dev))
      prod_id.add(prod[d.name]["id"]);
  });
  prod_id = [...prod_id];
  prod_id.map((x) => createOne({ query: graphQL_query(x) });
});

const callback = () => console.log("all done");

现在我的函数返回：

xyz - M5WBmnWs 
abc - QrqJ91Rq
qwe - VP0B0KEt

我怎么打电话给

callback

？让我的输出看起来像这样：

xyz - M5WBmnWs 
abc - QrqJ91Rq
qwe - VP0B0KEt
all done