试图将SEQUENCE号插入INSERT语句但有问题[重复]

Question

这个问题在这里已有答案：

• Error “Msg 245, Level 16, State 1, Line 22 Conversion failed when converting the varchar value 'July' to data type int.” 1回答

我正在尝试创建一个序列值，我需要在使用SQL Server 2014的INSERT语句中递增。我有一个变量，其中包含我试图插入临时表的最大数+ 1，但该数字需要对于插入TEMP TABLE的每个记录，递增。在谷歌搜索这个问题后，我发现我需要创建一个DYNAMIC SQL语句才能使用变量值。但是，当我这样做时，我现在得到一个转换错误。

任何帮助/方向将不胜感激。谢谢。

这是我的代码：

DECLARE @id int;
DECLARE @sql NVARCHAR(MAX);
SET @id = (SELECT MAX(rowNum)+1 FROM dbo.Focus_Export_Econ_DisadvantagedHHS_Staging_TEST)
SET @sql = 'CREATE SEQUENCE dbo.ID_Sequence
    AS INT
    START WITH ' + @id + 
    'INCREMENT BY 1
    NO MAXVALUE'
EXEC @sql;
SELECT NEXT VALUE FOR @sql, T.*
INTO #TEMP_TEST  --DROP TABLE #TEMP_TEST 
FROM (SELECT h.SiteID, st.SchoolName, st.CEPSchool, st.StudentID, st.FName, st.LName, st.Grade, UPPER(LEFT(h.Status,1))+LOWER(SUBSTRING(h.Status,2,LEN(h.Status))) as Status, 
        (CASE
            WHEN UPPER(h.Status) = 'FREE' THEN '01'
            WHEN UPPER(h.Status) = 'REDUCED' THEN '02'
            WHEN UPPER(h.Status) = 'PAID' THEN '00'
        END) as EconomicDisadvantageCode, 
        (CASE 
            WHEN ltrim(h.AppType) = 'HS Survey' THEN 'HH' 
        END) as ApplicationTypeCode,
        'HouseHold Survey' as ApplicationType,
        st.ResAddr, st.City, st.ZipCode, st.State, st.Phone, 
        CONVERT(VARCHAR(10), CAST(h.Effective_Date as date), 101) as StatusEffectiveDate, h.End_Date, st.SchoolYear, 
        st.BirthDate, st.AppScanned, st.AppOnline, st.GracePeriodID,
        (CASE
            WHEN ISNUMERIC(h.APPID) = 1 THEN CONVERT(INT, h.APPID) ELSE NULL 
        END) as ApplicationID 
    FROM #TEMP_HHS_Historical_Records h
    INNER JOIN dbo.Focus_Export_Econ_DisadvantagedHHS_Staging_TEST st
    ON h.CustomerID = st.StudentID) as T;

我得到的错误是：

Msg 245, Level 16, State 1, Line 384
Conversion failed when converting the varchar value 'CREATE SEQUENCE dbo.ID_Sequence
        AS INT
        START WITH ' to data type int.

Answer 1

你需要将ID转换为nvarchar，如下所示：

DECLARE @id int;
DECLARE @sql NVARCHAR(MAX);
SET @id = (SELECT MAX(rowNum)+1 FROM dbo.Focus_Export_Econ_DisadvantagedHHS_Staging_TEST)
SET @sql = 'CREATE SEQUENCE dbo.ID_Sequence
    AS INT
    START WITH ' + cast(@id as nvarchar(100)) + 
    'INCREMENT BY 1
    NO MAXVALUE'
   exec sp_executesql @sql;

--TO GET THE VALUE INTO @ID
SELECT  @id = NEXT VALUE FOR dbo.ID_Sequence

您只需要创建一次序列。您可以迭代并获取@id值。希望能帮助到你！

Answer 2

我认为问题出在动态SQL中。您可以通过以下方式解决此问题

SET @sql = 'CREATE SEQUENCE dbo.ID_Sequence
    AS INT
    START WITH ' + cast(@id as varchar(255) + '
    INCREMENT BY 1
    NO MAXVALUE'
EXEC (@sql);

我不确定create sequence语句是否允许参数，但这比使用像这样的值更改字符串更好。