下面是我的代码。如果我不以action =“ https://www.paypal.com/cgi-bin/webscr”形式使用此链接。数据形式成功插入到我的数据库中。但是，当我使用此操作链接时。在数据库中，表单数据未发送
所以，表单动作和发布方法如何一起工作？
实际上这是我想要的，单击提交按钮后，将标题数据成功插入到我的数据库中。然后页面重定向到PayPal结帐页面。
<?php
$database_username = 'root';
$database_password = '';
$pdo_conn = new PDO( 'mysql:host=localhost;dbname=shipping_pro', $database_username, $database_password );
if($_SERVER['REQUEST_METHOD'] == 'POST' && isset($_POST['insert'])) {
$sql = "INSERT INTO posts (title) VALUES (:title)";
$pdo_statement = $pdo_conn->prepare( $sql );
$result = $pdo_statement->execute( array(
':title'=>$_POST['title']
) );
if (!empty($result) ){
header('location:index.php');
}
}
?>
<form method="POST" action="https://www.paypal.com/cgi-bin/webscr">
<input type="text" name="title" placeholder="Title" />
<input name="insert" type="submit" value="Add">
</form>
[我刚刚快速测试了我在上面的评论中提到的use ajax and let the callback submit the form想法-似乎可以正常运行，因此很想知道为什么这对您不起作用-本质上，该表格对于Paypal而言在所有意图和目的上都将出现应当这样，所以我看不到为什么它不起作用（但可能还没有足够的咖啡吗？）
通过防止单击（e.preventDefault()）时SUBMIT按钮执行其默认操作，您可以中断表单的流程并可以在提交之前注入自己的逻辑。而不是立即发送表单，而是将所需的任何数据发送到PHP脚本，而是将其记录到db并发送给ajax函数一个答复，说“嗨，我已经完成-继续”等，然后回调实际上将继续提交表格。
<?php
if( $_SERVER['REQUEST_METHOD']=='POST' ){
ob_clean();
/* log details to db */
/*
$database_username = 'root';
$database_password = '';
$pdo_conn = new PDO( 'mysql:host=localhost;dbname=shipping_pro', $database_username, $database_password );
INSERT INTO posts (title) VALUES (:title) etc etc
*/
/* send some sort of response to ajax callback */
exit("banana's tend to be yellow and monkeys love 'em!");
}
?>
<!DOCTYPE html>
<html lang='en'>
<head>
<meta charset='utf-8' />
<title>Paypal: Record details to db and then submit to Paypal</title>
<script>
const ajax=function(url,params,callback){
let xhr=new XMLHttpRequest();
xhr.onload=function(){
if( this.status==200 && this.readyState==4 )callback.call( this, this.response )
};
xhr.onerror=function(e){
alert(e)
};
xhr.open( 'POST', url, true );
xhr.setRequestHeader('Content-Type','application/x-www-form-urlencoded');
xhr.setRequestHeader('X-Requested-With','XMLHttpRequest');
xhr.send( params );
};
const clickhandler=function(e){
e.preventDefault();
let form=this.parentNode;
const callback=function(r){
alert( 'Response from saving to db: '+r+'\nNow submit the form to PayPal!!!' );
form.submit();
};
ajax( location.href, 'title='+this.previousElementSibling.value, callback )
};
document.addEventListener('DOMContentLoaded', ()=>{
document.querySelector( 'form > input[type="submit"][name="insert"]' ).addEventListener( 'click', clickhandler )
});
</script>
</head>
<body>
<form method="POST" action="https://www.paypal.com/cgi-bin/webscr">
<input type='hidden' name='cmd' value='_s-xclick' />
<input type='hidden' name='hosted_button_id' value='S2QXVVPPL7EUE' />
<input type='hidden' name='on0' value='BANANA' />
<input type='hidden' name='os0' value='BANANA' />
<input type='hidden' name='currency_code' value='GBP' />
<input type="text" name="title" placeholder="Title" />
<input name="insert" type="submit" value="Add">
</form>
</body>
</html>
请尝试以下代码
<?php
$database_username = 'root';
$database_password = '';
$pdo_conn = new PDO( 'mysql:host=localhost;dbname=shipping_pro', $database_username, $database_password );
if($_SERVER['REQUEST_METHOD'] == 'POST' && isset($_POST['insert'])) {
$sql = "INSERT INTO posts (title) VALUES (:title)";
$pdo_statement = $pdo_conn->prepare( $sql );
$result = $pdo_statement->execute( array(
':title'=>$_POST['title']
) );
if (!empty($result) ){
header('location:https://www.paypal.com/cgi-bin/webscr')
}
}
?>
<form method="POST" action="index.php">
<input type="text" name="title" placeholder="Title" />
<input name="insert" type="submit" value="Add">
</form>