清理包含双引号值的 CSV 字符串

Question

我正在尝试解析和清理带有引号值的动态 CSV 字符串 (

$line

)。

echo "<pre>", print_r($line, 1), "</pre>";

字符串的格式如下：

"AARON,  ELVIA J",WATER RATE TAKER,WATER MGMNT,$81000.00,$73862.00

我需要更改字符串以删除引用值中的逗号、空格和引号，使其看起来像这样：

AARONELVIAJ,WATER RATE TAKER,WATER MGMNT,$81000.00,$73862.00

我做了什么：

$re1 = '(")';   # Any Single Character 1
$re2 = '((?:[a-z][a-z]+))'; # Word 1
$re3 = '(,)';   # Any Single Character 2
$re4 = '(\\s+)';    # White Space 1
$re5 = '((?:[a-z][a-z]+))'; # Word 2
$re6 = '(\\s+)';    # White Space 2
$re7 = '.*?';   # Non-greedy match on filler
$re8 = '(")';

$reg1 = "/" . $re1 . $re2 . "/";
$reg2 = "/" . $re3 . $re4 . "/";
$reg3 = "/" . $re5 . $re6 . $re7 . $re8 . "/";
$line = preg_replace("/" . '($reg1)$reg2($reg3)' . "/", "$1$2", $line); //this is also generating the same array "AARON,  ELVIA J",WATER RATE TAKER,WATER MGMNT,$81000.00,$73862.00
echo "<pre>", print_r($line, 1), "</pre>";
        
$pattern = "/" . $re1 . $re2 . $re3 . $re4 . $re5 . $re6 . $re7 . $re8 . "/";
$replacement = "/" . $re2 . $re5 . $re7 . "/";

$values = preg_replace($pattern, $replacement, $line);
$values = explode(',',$line);
echo "<br>";
$values = preg_replace('/[^A-Za-z0-9\-]/', '', $values);
$values = implode(',',$values);
echo "<pre>", print_r($values), "</pre>";
echo "<pre>", print_r($values, 1), "</pre>";

我得到的是这样的：

AARON,ELVIAJ,WATERRATETAKER,WATERMGMNT,8100000,73862001

我需要删除引号括起来的值中的内部逗号。

Answer 1

试试这个

    $line = '"AARON,  ELVIA J",WATER RATE TAKER,WATER MGMNT,$81000.00,$73862.00';
    $pieces = explode('"', $line);

    $result = '';
    foreach ($pieces as $value) {
    if(substr( $value, 0, 1 ) === "," || substr($value, -1) == ','){
        $result .= $value;
    }else{
        $value = str_replace(',', '', $value);
        $result .= str_replace(' ', '', $value);
    }
}
echo $result;

Answer 2

str_getcsv()函数将为您完美完成此操作。

$result = str_getcsv($line);

给予：

Array
(
    [0] => AARON,  ELVIA J
    [1] => WATER RATE TAKER
    [2] => WATER MGMNT
    [3] => $81000.00
    [4] => $73862.00
)

如果您确实想删除名称中的空格和逗号，那么您可以添加：

$result[0] = preg_replace('/\s+|,/', '', $result[0]);