JPA 在插入时复制列。多列作为主键和外键

Question

JPA 在尝试插入（列活动）时复制列，并且不会在其中一个参数中插入值。

错误如下：

could not execute statement [No value specified for parameter 6.] 
[insert into payment_item 
(account_id,x,y,active,payment_id,active,id) 
values (?,?,?,?,?,?,?)]

DDL 如下（为了解释而简化）：

CREATE TABLE payment_item (
    id BIGINT,
    payment_id BIGINT NOT NULL,
    active BOOLEAN NOT NULL DEFAULT true ,
    PRIMARY KEY (id, active),
    FOREIGN KEY (payment_id, active) REFERENCES payment (id, active)
) PARTITION BY LIST (active);

映射jpa：

public class PaymentItemKey implements Serializable {
    private Long id;

    private Boolean active = true;
}

@Entity
@Table(name = "payment_item")
@IdClass(PaymentItemKey.class)
public class PaymentItemEntity {

    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "payment_item_generator")
    @SequenceGenerator(name = "payment_item_generator", sequenceName = "payment_item_seq", allocationSize = 1)
    private Long id;

    @Id
    private boolean active = true;

    @ManyToOne
    @JoinColumns({
            @JoinColumn(name = "payment_id", referencedColumnName = "id"),
            @JoinColumn(name = "active", referencedColumnName = "active")
    })
    private PaymentEntity payment;

}

if 仅当我从主键中删除 active 时才有效。但这是必要的，因为我想使用活动列对表进行分区

请注意，如果我使用 Embedded 而不是 IdClass，则会出现相同的错误。

Answer 1

发生此错误是因为您试图声明具有相同名称的两个不同列。一列在代码

private boolean active = true;

中声明，第二列在代码

@JoinColumn(name = "active", referencedColumnName = "active")

中声明。要解决该问题，您需要删除其中一列或使用不同的名称。

我建议你去掉代码中的字段

private boolean active = true;

。由于

Payment

实体通过一对多关系与

PaymentItem

相关，因此其

active

字段会传播到每个嵌套项。

结果，我们得到以下映射。

@Entity
@IdClass(PaymentKey.class)
@Table(name = "payments")
public class Payment {

    @Id
    private Long id;

    @Id
    private Boolean active;

    @JsonManagedReference
    @OneToMany(mappedBy = "payment", cascade = CascadeType.ALL, orphanRemoval = true)
    private Set<PaymentItem> items;

  // ...
}

@Entity
@Table(name = "payment_items")
public class PaymentItem {

    @Id
    private Long id;

    @ManyToOne
    @JsonBackReference
    @JoinColumns({
            @JoinColumn(name = "payment_id"),
            @JoinColumn(name = "active")
    })
    private Payment payment;

  // ...
}

public class PaymentKey implements Serializable {
    
    private Long id;
    
    private Boolean active;
    
  // ...
}