在 Snowflake 中执行 Insert 语句时出现错误

Question

我在雪花大学做 Badge 3 并遇到错误。 ESS-DABW 徽章 3：数据应用程序构建器研讨会：第 5 课：待处理订单应用程序改进 🥋 完善 ORDERS 表定义。

下面是我在 Smoothies 数据库公共架构和订单表中的代码。

alter table SMOOTHIES.PUBLIC.ORDERS 
add column order_uid integer --adds the column
default smoothies.public.order_seq.nextval  --sets the value of the column to sequence
constraint order_uid unique enforced; --makes sure there is always a unique value in the column

create or replace table smoothies.public.orders (
       order_uid integer default smoothies.public.order_seq.nextval,
       order_filled boolean default false,
       name_on_order varchar(100),
       ingredients varchar(200),
       constraint order_uid unique (order_uid),
       order_ts timestamp_ltz default current_timestamp()
);

插入不起作用的语句：

insert into smoothies.public.orders 
values ('Guava Cantaloupe Elderberries ', 'Abhi');

错误信息

插入值列表与期望 5 但得到 2 的列列表不匹配

我的 Streamlit 代码：

# Import python packages
import streamlit as st
from snowflake.snowpark.functions import col
from snowflake.snowpark.context import get_active_session

# Write directly to the app
st.title(":cup_with_straw: Customize Your Smoothie! :cup_with_straw:")
st.write(
    """Choose the fruits you want in your custom Smoothie!
    """
)

name_on_order= st.text_input('Name on Smoothie')
st.write('The name on your Smoothie will be:', name_on_order)


session= get_active_session()
my_dataframe = session.table("smoothies.public.fruit_options").select(col('Fruit_name'))
#st.dataframe(data=my_dataframe, use_container_width=True)
ingredients_list = st.multiselect('Choose up to 5 ingredients:', my_dataframe
)

if ingredients_list:
    #st.write(ingredients_list)
    #st.text(ingredients_list)
    ingredients_string= ''
    for fruit_chosen in ingredients_list:
        ingredients_string+=fruit_chosen + ' '
    #st.write(ingredients_string)

    my_insert_stmt = """ insert into smoothies.public.orders
        values ('""" + ingredients_string + """','""" + name_on_order+ """')"""

    #st.write(my_insert_stmt)
    #st.stop()
    time_to_insert= st.button('Submit Order')
    if time_to_insert:
        session.sql(my_insert_stmt).collect()
        st.success('Your Smoothie is ordered!', icon="✅")

Streamlit 应用程序图像

Streamlit 应用程序错误图像

Answer 1

如果您不提供明确的列列表，则这些值将与所有列匹配，正如错误所示 - 您有五列，但只有两个值。

假设您打算保留包含默认值的列，则可以显式列出没有默认值的列：

insert into smoothies.public.orders 
(name_on_order, ingredients) -- Here
values ('Guava Cantaloupe Elderberries ', 'Abhi');