GitHub 操作：Supabase Postgres 容器无法初始化，并显示“用户 supabase_admin 密码验证失败

Question

我正在尝试设置一个 GitHub Actions 工作流程，它将启动 supabase 数据库作为一个步骤，我最终想运行我在 Django 中编写的测试，但是当尝试启动 Supabase Postgres 容器时出现这些初始化错误。这是我当前的配置和错误：

Error message:
/usr/local/bin/docker-entrypoint.sh: running /docker-entrypoint-initdb.d/migrate.sh
   [local] 2024-10-31 01:36:07.736 UTC [75] supabase_admin@test_db FATAL:  password authentication failed for user "supabase_admin"
   [local] 2024-10-31 01:36:07.736 UTC [75] supabase_admin@test_db DETAIL:  Role "supabase_admin" does not exist.
    Connection matched pg_hba.conf line 82: "local all  supabase_admin     scram-sha-256"
  Error: Failed to initialize container supabase/postgres:15.6.1.133
Error: One or more containers failed to start.

当前 GitHub Actions 工作流程配置：

services:
  postgres:
    image: supabase/postgres:15.6.1.133
    env:
      POSTGRES_USER: postgres
      POSTGRES_PASSWORD: ****
      POSTGRES_DB: test_db
      DATABASE_URL: postgres://postgres:postgres@localhost:5432/test_db
    ports:
      - 5432:5432
    options: >-
      --health-cmd="pg_isready -U postgres"
      --health-interval=10s
      --health-timeout=5s
      --health-retries=5

Answer 1

调查了您的问题，但无法查明其具体根本原因。显然，这是 SUPABASE 特有的东西。您可能想在他们的存储库上打开一个问题以获得对此的澄清。

但是，这对我有用：

name: supabase_services_container

on: workflow_dispatch

jobs:
  ci:
    runs-on: ubuntu-latest

    services:
      postgres:
        image: supabase/postgres:15.6.1.133
        env:
          POSTGRES_PASSWORD: postgres
          POSTGRES_DB: test_db
        ports:
        - 5432:5432
        options: >-
          --health-cmd=pg_isready
          --health-interval=10s
          --health-timeout=5s
          --health-retries=5

    steps:
      - name: Install postgresql-client (psql)
        run: |
          sudo apt update -y
          sudo apt install -y postgresql-client
          psql --version

      - name: Check
        run: |
          psql "postgresql://postgres:postgres@localhost:5432" <<EOF
            CREATE TABLE test (id INT);
            INSERT INTO test (id) VALUES (123);
            INSERT INTO test (id) VALUES (456);
            INSERT INTO test (id) VALUES (789);
            SELECT * FROM test;
          EOF

输出：