我刚刚从Instragram收到一个扩展名为.json的文件中的我喜欢的数据。
{"media_likes": [["2019-12-10T17:49:02", "feojo"],
["2019-12-10T14:11:53", "sollylun"],
["2016-02-16T17:05:43", "ser_mart"]],
"comment_likes":[["2019-11-28T18:05:04", "kerslyrikatel"],
["2019-11-28T18:05:03", "jakar"],
["2019-12-10T14:11:53", "sollylun"]]}
我可以在值列中返回子数组,但不知道是谁将那些数组转换为'date'和'user'列:
DECLARE @JSON1 NVARCHAR(MAX)
SELECT @JSON1 = '{
"media_likes": [
["2019-12-10T17:49:02", "feonaleejones"],
["2019-12-10T14:11:53", "sollyluna021"],
["2016-02-16T17:05:43", "serene_martin"]
],
"comment_likes":[
["2019-11-28T18:05:04", "kerstinslyrikatelier"],
["2019-11-28T18:05:03", "jan.kart"],
["2019-12-10T14:11:53", "sollyluna021"]
]
}'
SELECT [key],value
FROM OPENJSON(@JSON1,'$.media_likes')
key value
0 ["2019-12-10T17:49:02", "feonaleejones"]
1 ["2019-12-10T14:11:53", "sollyluna021"]
2 ["2016-02-16T17:05:43", "serene_martin"]
如何旋转两个数组的值?
约翰
select
DECLARE @JSON1 NVARCHAR(MAX)
SELECT @JSON1 = '{
"media_likes": [
["2019-12-10T17:49:02", "feonaleejones"],
["2019-12-10T14:11:53", "sollyluna021"],
["2016-02-16T17:05:43", "serene_martin"]
],
"comment_likes":[
["2019-11-28T18:05:04", "kerstinslyrikatelier"],
["2019-11-28T18:05:03", "jan.kart"],
["2019-12-10T14:11:53", "sollyluna021"]
]
}'
SELECT likedate,userlike
FROM OPENJSON(@JSON1,'$.media_likes')
WITH (
likedate datetime '$[0]',
userlike varchar(128) '$[1]'
)