在PostgreSQL中使用交叉表将行转换为列不起作用（关系“表”不存在）

Question

我需要使用CTE使用已编译的数据，然后在下一个select语句中使用crosstab（将其转换为其他想法）将列转换为行。下面是查询。

    with checked_adgroup AS (
         SELECT 
            ua.new_adgroup,
            ua.account,
            ua.campaign,
            ua.ad_group,
            ua."position",
            cp.category,
            pt.full_value,

   FROM unnest_adgroup ua
     LEFT JOIN taxonomy_category cp ON ua."position" = cp."position"
     LEFT JOIN taxonomy pt ON ua.short_val = pt.short_value AND cp.category = pt.category AND (pt.lob IS NULL OR pt.lob = ua.lob)
         )

        SELECT * 
        from crosstab(
        'select
        cad.account,
        cad.campaign,
        cad.ad_group,
        cad.category,
        cad.full_value
        FROM checked_adgroup cad 
        WHERE  cad.all_correct AND cad.category IS NOT NULL
        ORDER BY 1,2,3')
        AS final_result( 
         account text, campaign text, ad_group text,
         division text, lob text, match_type text  );

错误消息：错误：关系“ checked_adgroup”不存在第7行：FROM Checked_adgroup cad

checked_adgroup cte的输出如下所示：

enter image description here

最终声明的期望输出是：

enter image description here

Answer 1

欢迎社区。首先，请不要发布图片，因为它们无法使用，在某些情况下它们是被禁止的并且无法查看。而是使用格式化的文本。我没有太多使用交叉表功能，但是它确实提供了包含两个查询的第二个版本，第二个馈入了第一个查询。但是，您发布的查询中存在几个错误，需要以任何一种方式进行更正。首先。寻找-<

   with checked_adgroup AS (
         SELECT 
            ua.new_adgroup,
            ua.account,
            ua.campaign,
            ua.ad_group,
            ua."position",
            cp.category,
            pt.full_value,
            --<< missing column or ending , above should not be there, assumption missing column see below. 
   FROM unnest_adgroup ua
     LEFT JOIN taxonomy_category cp ON ua."position" = cp."position"
     LEFT JOIN taxonomy pt ON ua.short_val = pt.short_value AND cp.category = pt.category AND (pt.lob IS NULL OR pt.lob = ua.lob)
         )

    SELECT * 
    from crosstab(
    'select
    cad.account,
    cad.campaign,
    cad.ad_group,
    cad.category,
    cad.full_value
    FROM checked_adgroup cad 
    WHERE  cad.all_correct AND cad.category IS NOT NULL
    --<< above line has 2 errors:
    --<< Incorrectly formatted needs to cad.all_correct is not null AND cad.category IS NOT NULL
    --<< column cad.all_correct does not exist (see missing column above  
    ORDER BY 1,2,3')
    AS final_result( 
     account text, campaign text, ad_group text,
     division text, lob text, match_type text);  

现在，我们需要将CTE转换为交叉表可能很适合使用的第二个查询。我已经用Postgres $ Quoting $标识了每个对象，并不是因为有必要，而是因为标准字符串引号（'）就足够了，而更多的是从可见性角度出发。

select * 
   from crosstab(
    $ct1$select
               account,
               campaign,
               ad_group,
               category,
               full_value
         --<< from checked_adgroup cad 
         --<< where cad.all_correct and cad.category is not null
         --<< moved above lines to second query to avoid reference and removed qualification  
         order by 1,2,3
     $ct1$ 
   , $ct2$select * 
            from (
                  select 
                        ua.new_adgroup,
                        ua.account,
                        ua.campaign,
                        ua.ad_group,
                        ua."position",
                        cp.category,
                        pt.full_value,
                        'mssing from orig posted query'  all_correct
                   from unnest_adgroup ua
                   left join taxonomy_category cp on ua."position" = cp."position"
                   left join taxonomy pt on ua.short_val = pt.short_value 
                                        and cp.category = pt.category 
                                        and (pt.lob is null or pt.lob = ua.lob)
                 ) s                    
           where all_correct is not null and cad.category is not null
           --<< move from query1 
       $ct2$ )
  as final_result( 
     account text, campaign text, ad_group text,
     division text, lob text, match_type text  );

但是现在我得到一个错误关系unnest_adgroup不存在。这是正确的，因为您没有发布定义，也没有发布其他引用的表。但这似乎暗示语法是正确的。诚然，如果这样的话，这可能是不合时宜的，所以，我以后总是可以删除。但是，目前我没有其他项目，只能呆在家里，这似乎是一个有趣的问题。期待结果。祝好运。