从 Raspberry Pi 捕获 jpeg 图像并将其发送到 PC 套接字 python？

Question

我想将 Rasberry pi 相机捕获的图像像流一样实时发送到 PC，但不是流，因为我没有那么多带宽。 我现在拥有的代码是。

客户

import io
import cv2
import socket
import struct
from PIL import Image
import numpy

# Start a socket listening for connections on 0.0.0.0:8000 (0.0.0.0 means
# all interfaces)
cv2.namedWindow('Network Image')
server_socket = socket.socket()
server_socket.bind(('0.0.0.0', 8200))
server_socket.listen(0)

# Accept a single connection and make a file-like object out of it
connection = server_socket.accept()[0].makefile('rb')
try:
    while True:
        # Read the length of the image as a 32-bit unsigned int. If the
        # length is zero, quit the loop
        image_len = struct.unpack('<L', connection.read(struct.calcsize('<L')))[0]
        if not image_len:
            break
        # Construct a stream to hold the image data and read the image
        # data from the connection
        image_stream = io.BytesIO()
        image_stream.write(connection.read(image_len))
        # Rewind the stream, open it as an image with PIL and do some
        # processing on it
        image_stream.seek(0)
        image = Image.open(image_stream).convert('RGB')
        open_cv_image = numpy.array(image)
        open_cv_image = open_cv_image[:, :, ::-1].copy()
        cv2.imshow('Network Image',open_cv_image)
        cv2.waitKey(0)
        print('Image is %dx%d' % image.size)
        image.verify()
        print('Image is verified')
finally:
    connection.close()
    server_socket.close()
    image_stream.close()

服务器

import io
import socket
import struct
import time
import picamera

# Connect a client socket to my_server:8000 (change my_server to the
# hostname of your server)
client_socket = socket.socket()
client_socket.connect(('192.168.2.225', 8200))

# Make a file-like object out of the connection
connection = client_socket.makefile('wb')
try:
    with picamera.PiCamera() as camera:
        camera.framerate=15
        camera.resolution = (480, 480)
        # Start a preview and let the camera warm up for 2 seconds
        camera.start_preview()
        time.sleep(2)

        # Note the start time and construct a stream to hold image data
        # temporarily (we could write it directly to connection but in this
        # case we want to find out the size of each capture first to keep
        # our protocol simple)
        start = time.time()
        stream = io.BytesIO()
        for foo in camera.capture_continuous(stream, 'jpeg'):
            # Write the length of the capture to the stream and flush to
            # ensure it actually gets sent
            connection.write(struct.pack('<L', stream.tell()))
            connection.flush()
            # Rewind the stream and send the image data over the wire
            stream.seek(0)
            connection.write(stream.read())
            # If we've been capturing for more than 30 seconds, quit
            if time.time() - start > 30:
                break
            # Reset the stream for the next capture
            stream.seek(0)
            stream.truncate()
    # Write a length of zero to the stream to signal we're done
    connection.write(struct.pack('<L', 0))
finally:
    connection.close()
    client_socket.close()
    image_stream.close()

我可以以某种方式提高效率吗？ 理想情况下，我想捕获一帧并保存为 jpeg 并以 30 FPS 传输到客户端。 现在我的帧速率约为 8 FPS。

Answer 1

使用

client_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
for foo in camera.capture_continuous(stream, 'jpeg', use_video_port = True):