如何检查值是增加还是增加 - PHP

问题描述 投票:0回答:2

我正在编写一个脚本来检查日期的增加,以了解是否要向现有变量添加值。虽然我已经能够在这里得到一些帮助,但仍然看起来我仍然坚持检查一天是否增加了。

PHP代码

<?php
 $now = time(); // or your date as well
 $your_date = strtotime("2018-09-05");
 $datediff = $now - $your_date;

 $alreadySpentDays = round($datediff / (60 * 60 * 24));

 $userEarnings = 0;

 // i want to be able to check if the day has increased and if it has i want to be able to add $10 to userEarning variable daily
?>
<p><?=$userEarnings?></p>
php date
2个回答
1
投票

每天计算它没有意义,只需在需要时进行计算。 $ start_date是您要开始计算的日期,其中收入为0。 然后计算经过的天数并乘以10。

$now = time(); // or your date as well
$start_date = strtotime("2018-09-04");
$datediff = $now - $start_date;

$alreadySpentDays = round($datediff / (60 * 60 * 24));
echo $alreadySpentDays * 10; // 20, since it's two days of earnings (september 4 and 5)

0
投票

使用DateTime :: diff(http://php.net/manual/en/datetime.diff.php

$userEarnings = 0;
$now = new DateTime(); //now
$your_date = new DateTime("2010-09-05");

$diff = $now->diff($your_date);

if ($diff->days > 0) {
    $userEarnings += 10;
}
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