1 行到 1 列的数据透视表

Question

我有一个查询，使用以下查询输出 7 天内的每日传送带启动时间：

Select 
    format(min(case when location = 0 and scantime between getdate()-1 and getdate() then scantime end),'hh:mm:ss:tt') [StartTime1]
    ,format(min(case when location = 0 and scantime between getdate()-2 and getdate()-1 then scantime end),'hh:mm:ss:tt') [StartTime2]
    ,format(min(case when location = 0 and scantime between getdate()-3 and getdate()-2 then scantime end),'hh:mm:ss:tt') [StartTime3]
    ,format(min(case when location = 0 and scantime between getdate()-4 and getdate()-3 then scantime end),'hh:mm:ss:tt') [StartTime4]
    ,format(min(case when location = 0 and scantime between getdate()-5 and getdate()-4 then scantime end),'hh:mm:ss:tt') [StartTime5]
    ,format(min(case when location = 0 and scantime between getdate()-6 and getdate()-5 then scantime end),'hh:mm:ss:tt') [StartTime6]
    ,format(min(case when location = 0 and scantime between getdate()-7 and getdate()-6 then scantime end),'hh:mm:ss:tt') [StartTime7]
    
  FROM [BaldorFoods_WcsDb].[dbo].[ScanLog]
  where datepart(hour,scantime) in (18,19,20,21,22,23,0,1,2,3,4,5,6)

这会输出图像中的表格：MyTable。我将如何更改此表，以便将行名称标记为 StartTime1、StartTime2、StartTime3.... 等。

我尝试使用数据透视表函数，但在指定函数的输入时遇到困难。

Answer 1

我会采取不同的方法

select format(scantime, 'hh:mm:ss:tt')
from (values
  (0),
  (1),
  (2),
  (3),
  (4),
  (5),
  (6)
) as up(n)
cross apply (
  select top(1) scantime
  from [BaldorFoods_WcsDb].[dbo].[ScanLog]
  where datepart(hour,scantime) in (18,19,20,21,22,23,0,1,2,3,4,5,6)
    and scantime between getdate() - up.n and getdate() - (up.n-1)
  order by scantime
) as d;

为了解释，我们来分解一下。这是一个更简单的版本，只为您提供日期边界：

select n, getdate() - up.n, getdate() - (up.n-1)
from (values
  (0),
  (1),
  (2),
  (3),
  (4),
  (5),
  (6)
) as up(n)

从那里，我们使用

cross apply

获取第一行（按扫描时间列排序），该行位于给定的一组日期边界内，并且还应用了小时部分的谓词。