构建静态链接的 pysqlite3 库

Question

我正在尝试按照构建静态链接库来编译 SQLite3 并将其导入到 Python3 中，但是我无法让它工作。我已经从源代码编译，复制了 .c 和 .h 文件，运行

python setup.py build_static build

，但它不起作用。

❯ find . -name "_sqlite3*.so"
./build/lib.macosx-14.0-arm64-cpython-312/pysqlite3/_sqlite3.cpython-312-darwin.so

❯ python3 -c "import sys; print(sys.path)"
['', '/opt/homebrew/Cellar/[email protected]/3.12.6/Frameworks/Python.framework/Versions/3.12/lib/python312.zip', '/opt/homebrew/Cellar/[email protected]/3.12.6/Frameworks/Python.framework/Versions/3.12/lib/python3.12', '/opt/homebrew/Cellar/[email protected]/3.12.6/Frameworks/Python.framework/Versions/3.12/lib/python3.12/lib-dynload', '/Users/myusername/Library/Python/3.12/lib/python/site-packages', '/opt/homebrew/lib/python3.12/site-packages', '/opt/homebrew/lib/python3.12/site-packages/pysqlite3-0.5.4-py3.12-macosx-14.0-arm64.egg', '/opt/homebrew/opt/[email protected]/libexec']

但是，然后尝试导入它不起作用：

from pysqlite3 import dbapi2 as sqlite3

Traceback (most recent call last):
  File "/Users/username/Sandbox/sqlite3ttt/pysqlite3/a.py", line 1, in <module>
    from pysqlite3 import dbapi2 as sqlite3
  File "/Users/username/Sandbox/sqlite3ttt/pysqlite3/pysqlite3/__init__.py", line 23, in <module>
    from pysqlite3.dbapi2 import *
  File "/Users/username/Sandbox/sqlite3ttt/pysqlite3/pysqlite3/dbapi2.py", line 28, in <module>
    from pysqlite3._sqlite3 import *
ModuleNotFoundError: No module named 'pysqlite3._sqlite3'

Answer 1

错误是因为当前目录下有一个名为

pysqlite3

的子目录，隐藏了

build/lib.macosx-14.0-arm64-cpython-312/pysqlite3

。

在您运行的目录中

find . -name "_sqlite3*.so"

，执行以下命令：

export PYTHONPATH="$PWD/build/lib.macosx-14.0-arm64-cpython-312"
cd /tmp
python3 -c "from pysqlite3 import dbapi2 as sqlite3" # <- should not print error