Makefile 帮助目标

Question

我正在尝试创建一个漂亮且动态的帮助，但我正在努力解释项目的 .env 文件中的变量名称。我需要 .env 来解释这些名称。我将提供我能够达到的最接近的结果，但我无法取得任何进一步的进展。

在上图中，我标记了需要由.env解释的文本

这是代码：

SHELL := /bin/bash
include .env

ENV_FILE = .env

help:  ## Show help.
    @awk 'BEGIN { \
        FS = ":.*##"; \
        printf "\nUsage:\n  make \033[0;34m<target>\033[0m\n\nTargets:\n" \
    } \
    /^[a-zA-Z_\/\-\$${}]+:.*?##/ { \
        targetName = $$1; \
        description = $$2; \
        if (match(targetName, "\\$\\{([^}]+)\\}")) { \
            varEnvName = substr(targetName, RSTART+1, RLENGTH-2); \
            gsub("\\$$\\{[a-zA-Z_]+\\}", varEnvName, targetName); \
        }; \
        printf "  \033[0;34m%-10s\033[0m %s\n", targetName, description \
    }' $(MAKEFILE_LIST)

call/${DOCKER_PHP_CONTAINER_NAME}/a: ## PHP // Help dynamic.
    @echo "Dynamic target running for ${DOCKER_PHP_CONTAINER_NAME}"

call/${DOCKER_NGINX_CONTAINER_NAME}/a: ## NGINX // Help dynamic.
    @echo "Dynamic target running for ${DOCKER_NGINX_CONTAINER_NAME}"

call/bpro_php/b: ## Help fixed.
    @echo "Fixed target running..."

Answer 1

我做到了:)

我不确定这是否是最佳解决方案，但它对我有用。

help:  ##           Show help.
@set -a; source .env &>/dev/null; set +a; \
awk -v ENV_FILE=".env" ' \
BEGIN { \
    FS = ":.*##"; \
    printf "\nUsage:\n  make \033[0;34m<target>\033[0m\n\nTargets:\n" \
} \
/^[a-zA-Z_\/\-\$${}]+:.*?##/ { \
    targetName = $$1; \
    description = $$2; \
    while ((getline < ENV_FILE) > 0) { \
        if ($$0 ~ /^[^#[:space:]]/) { \
            gsub(/=.*/, "", $$0); \
            varName = $$0; \
            varValue = ENVIRON[varName]; \
            gsub("\\$\\{" varName "\\}", varValue, targetName); \
            gsub(/\$$/, "", targetName); \
        } \
    } \
    printf "  \033[0;34m%-10s\033[0m %s\n", targetName, description; \
    close(ENV_FILE); \
}' $(MAKEFILE_LIST)