我有一对一关系的Post和User模型,它运作良好:
//User.php
public function post(){
return $this->hasOne(Post::class);
}
// Post.php
public function user() {
return $this->belongsTo(User::class);
}
现在我创建API资源:
php artisan make:resource Post
php artisan make:resource User
我需要通过api调用返回所有帖子然后我设置我的路线:
//web.php: /resource/posts
Route::get('/resource/posts', function () {
return PostResource::collection(Post::all());
});
这是我的帖子资源类:
<?php
namespace App\Http\Resources;
use Illuminate\Http\Resources\Json\Resource;
use App\Http\Resources\User as UserResource;
class Posts extends Resource
{
/**
* Transform the resource into an array.
*
* @param \Illuminate\Http\Request $request
* @return array
*/
public function toArray($request)
{
return [
'id' => $this->id,
'title' => $this->title,
'slug' => $this->slug,
'bodys' => $this->body,
'users' => UserResource::collection($this->user),
'published' => $this->published,
'created_at' => $this->created_at,
'updated_at' => $this->updated_at,
];
}
}
这是错误:
Call to undefined method Illuminate\Database\Query\Builder::mapInto()
如果我删除:
'users' => UserResource::collection($this->user),
它的工作,但我需要在我的api json中包含关系,我已阅读并关注https://laravel.com/docs/5.5/collections的文档。
这是我的用户资源类:
```
namespace App\Http\Resources;
use Illuminate\Http\Resources\Json\Resource;
class User extends Resource
{
/**
* Transform the resource into an array.
*
* @param \Illuminate\Http\Request $request
* @return array
*/
public function toArray($request)
{
return [
'user_id' => $this->user_id,
'name' => $this->name,
'lastname' => $this->lastname,
'email' => $this->email
];
}
}
任何想法我错在哪里?
问题是你使用UserResource::collection($this->user)
并且你只有一个元素而不是集合所以你可以用new UserResource($this->user)
替换它:
return [
'id' => $this->id,
'title' => $this->title,
'slug' => $this->slug,
'bodys' => $this->body,
'users' => new UserResource($this->user),
'published' => $this->published,
'created_at' => $this->created_at,
'updated_at' => $this->updated_at,
];