如何使用urllib.parse.urlencode编码纬度和经度？

Question

我正在使用Google API获取附近咖啡店的json数据。为此，我需要将纬度和经度编码为URL。

所需的URL：https://maps.googleapis.com/maps/api/place/textsearch/json?query=coffee&location=22.303940,114.170372&radius=1000&maxprice=3&key=myAPIKey

我使用urlencode获取的URL：https://maps.googleapis.com/maps/api/place/textsearch/json?query=coffee&location=22.303940%2C114.170372&radius=1000&maxprice=3&key=myAPIKEY

如何删除网址中的“％2C”？ （我在下面显示了我的代码）

serviceurl_placesearch = 'https://maps.googleapis.com/maps/api/place/textsearch/json?'
    parameters = dict()
    query = input('What are you searching for?')     
    parameters['query'] = query

parameters['location'] = "22.303940,114.170372"

while True:
    radius = input('Enter radius of search in meters: ')
    try:
        radius = int(radius)
        parameters['radius'] = radius
        break
    except:
        print('Please enter number for radius')

while True:
    maxprice = input('Enter the maximum price level you are looking for(0 to 4): ')
    try:
        maxprice = int(maxprice)
        parameters['maxprice'] = maxprice
        break
    except:
        print('Valid inputs are 0,1,2,3,4')
parameters['key'] = API_key

url = serviceurl_placesearch + urllib.parse.urlencode(parameters)

我添加了这段代码以使URL起作用，但是我认为这不是一个长期解决方案。我正在寻找更长期的解决方案。

urlparts = url.split('%2C')
url = ','.join(urlparts)

Answer 1

您可以添加safe=","

import urllib.parse

parameters = {'location': "22.303940,114.170372"}

urllib.parse.urlencode(parameters, safe=',')

结果

location=22.303940,114.170372