在菜单的底部位置抽屉元

Question

怎么可能到菜单点在屏幕的下边缘的位置？最好的解决办法是，如果你可以简单地改变每个元素的导航选项的风格。

这里是我的应用程序导航：

    const AppNavigator = createDrawerNavigator(
      {
        Einkaufsliste: {
          screen: MainScreen,
          navigationOptions: {
            drawerIcon: <Icon name="shopping-cart" />
          }
        },
        Bearbeiten: {
          screen: BasketEditScreen,
          navigationOptions: {
            drawerIcon: <Icon name="edit" />
          }
        }
      },

      {
        contentComponent: CustomDrawerComponent
      }
    );

谢谢！

Answer 1

据react-navigation你可以做一个自定义的抽屉导航，所以你需要的是建立一个类似的事情自己的例子：

import { DrawerItems, SafeAreaView } from 'react-navigation';

const CustomDrawerContentComponent = (props) => (
  <ScrollView>
    <SafeAreaView style={styles.container} forceInset={{ top: 'always', horizontal: 'never' }}>
      <DrawerItems {...props} />
    </SafeAreaView>
  </ScrollView>
);

const styles = StyleSheet.create({
  container: {
    flex: 1,
  },
});

所以你的情况，你想要做的是：

    import { DrawerItems, SafeAreaView } from 'react-navigation';

    const CustomDrawerContentComponent = (props) => (
      <ScrollView>
        <SafeAreaView style={styles.container} forceInset={{ top: 'always', horizontal: 'never' }}>
        <View style={{flex: 1 }}>
              <DrawerItems {...props} />
        </View>
        <TouchableOpacity style={{flexDirection: 'row', alignItems: 'center'}}>
              //Your pencil icon here with correct margin to the right
              <Text>Bearbeiten</Text>
        </TouchableOpacity>
        </SafeAreaView>
      </ScrollView>
    );

    const styles = StyleSheet.create({
      container: {
        flex: 1,
      },
    });