我正在尝试在视图中连接 3 个表;情况是这样的:
我有一张表,其中包含申请住在该大学校园的学生的信息。我有另一个表格,列出了每个学生的大厅偏好(其中 3 个)。但这些偏好中的每一个都只是一个ID号,而ID号在第三个表中有对应的大厅名称(没有设计这个数据库......)。
几乎,我在桌子上有
INNER JOIN
,上面写着他们的喜好,以及他们的信息,结果就像......
John Doe | 923423 | Incoming Student | 005
其中
005
就是 HallID
。所以现在我想将 HallID
与第三个表相匹配,其中该表包含 HallID
和 HallName
。
非常好,我希望我的结果是这样的......
John Doe | 923423 | Incoming Student | Foley Hall <---(INSTEAD OF 005)
这是我目前拥有的:
SELECT
s.StudentID, s.FName,
s.LName, s.Gender, s.BirthDate, s.Email,
r.HallPref1, r.HallPref2, r.HallPref3
FROM
dbo.StudentSignUp AS s
INNER JOIN RoomSignUp.dbo.Incoming_Applications_Current AS r
ON s.StudentID = r.StudentID
INNER JOIN HallData.dbo.Halls AS h
ON r.HallPref1 = h.HallID
您可以执行以下操作(我猜测是表字段等)
SELECT s.studentname
, s.studentid
, s.studentdesc
, h.hallname
FROM students s
INNER JOIN hallprefs hp
on s.studentid = hp.studentid
INNER JOIN halls h
on hp.hallid = h.hallid
根据您对多个大厅的要求,您可以这样做。您只需为每个房间偏好 ID 多次加入大厅表即可:
SELECT s.StudentID
, s.FName
, s.LName
, s.Gender
, s.BirthDate
, s.Email
, r.HallPref1
, h1.hallName as Pref1HallName
, r.HallPref2
, h2.hallName as Pref2HallName
, r.HallPref3
, h3.hallName as Pref3HallName
FROM dbo.StudentSignUp AS s
INNER JOIN RoomSignUp.dbo.Incoming_Applications_Current AS r
ON s.StudentID = r.StudentID
INNER JOIN HallData.dbo.Halls AS h1
ON r.HallPref1 = h1.HallID
INNER JOIN HallData.dbo.Halls AS h2
ON r.HallPref2 = h2.HallID
INNER JOIN HallData.dbo.Halls AS h3
ON r.HallPref3 = h3.HallID
如果你有3个相同
ID
的桌子要加入,我想会是这样的:
SELECT * FROM table1 a
JOIN table2 b ON a.ID = b.ID
JOIN table3 c ON a.ID = c.ID
只需将
*
替换为您想要从表格中获取的内容即可。
SELECT column_Name1,column_name2,......
From tbl_name1,tbl_name2,tbl_name3
where tbl_name1.column_name = tbl_name2.column_name
and tbl_name2.column_name = tbl_name3.column_name
SELECT table1.col,table2.col,table3.col
FROM table1
INNER JOIN
(table2 INNER JOIN table3
ON table3.id=table2.id)
ON table1.id(f-key)=table2.id
AND //add any additional filters HERE
您只需要第二个内部联接,将您现在拥有的
ID Number
链接到第三个表的 ID Number
。然后,将 ID Number
替换为 Hall Name
,瞧:)
SELECT *
FROM
PersonAddress a,
Person b,
PersonAdmin c
WHERE a.addressid LIKE '97%'
AND b.lastname LIKE 'test%'
AND b.genderid IS NOT NULL
AND a.partyid = c.partyid
AND b.partyid = c.partyid;
已经有很多回复,但总体教训似乎是您可以在 where 子句中使用多个 JOINS;如果您有其他问题并且只想尝试解决问题,techonthenet.com(我的老板向我推荐了它,我就是这样找到它的)也有很好的 SQL 教程。
SELECT table1.column1
FROM table1
WHERE table1 > 0 (or whatever you want to specify)
INNER JOIN table1
ON table1.column1 = table2.column1
这是对具有相同 id 的连接 3 个表的正确查询**
select a.empname,a.empsalary,b.workstatus,b.bonus,c.dateofbirth
from employee a, Report b,birth c
where a.empid=b.empid and a.empid=c.empid and b.empid='103';
员工第一桌。 报告第二个表。 出生第三表
SELECT
A.P_NAME AS [INDIVIDUAL NAME],B.F_DETAIL AS [INDIVIDUAL FEATURE],C.PL_PLACE AS [INDIVIDUAL LOCATION]
FROM
[dbo].[PEOPLE] A
INNER JOIN
[dbo].[FEATURE] B ON A.P_FEATURE = B.F_ID
INNER JOIN
[dbo].[PEOPLE_LOCATION] C ON A.P_LOCATION = C.PL_ID
此查询适合您
Select b.id as 'id', u.id as 'freelancer_id', u.name as
'free_lancer_name', p.user_id as 'project_owner', b.price as
'bid_price', b.number_of_days as 'days' from User u, Project p, Bid b
where b.user_id = u.id and b.project_id = p.id
select products.product_id, product_name, price, created_at, image_name, categories.category_id, category_name,brands.brand_id, brand_name
FROM products INNER JOIN categories USING (category_id) INNER JOIN brands USING(brand_id)
select empid,empname,managename,[Management ],cityname
from employees inner join Managment
on employees.manageid = Managment.ManageId
inner join CITY on employees.Cityid=CITY.CityId
id name managename managment cityname
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