我正在尝试从包含在某些(但不是全部)输入元素中的数组中提取和合并对象。使用JOLT JSON转换库。
此外,我正在尝试合并的数组包含并不总是具有相同属性的对象。一些密钥可能存在于某些密钥中,但其他密钥则不存在
示例是人为/无意义的简化,但具有我们数据的一般形式。
输入:
{
"Widgets": [
{
"Id": "1",
"PetFriendly": "True",
"Features": [
{
"Name": "Easy Button",
"Type": "Button"
},
{
"Name": "Lunch Lever",
"Type": "Food Service",
"MenuItems": [
"Pizza",
"Cheezburger"
]
}
]
},
{
"Id": "2",
"PetFriendly": "True"
},
{
"Id": "3",
"PetFriendly": "False",
"Features": [
{
"Name": "Missles",
"Type": "Attack"
}
]
},
{
"Id": "4",
"PetFriendly": "False",
"Features": [
{
"Name": "Bombs",
"Type": "Attack",
"MenuItems": [
"Rat Poison"
]
}
]
}
]
}
期望的输出:
{
"Widgets": [
{
"Id": "1"
"PetFriendly": "True"
},
{
"Id": "2"
"PetFriendly": "True"
},
{
"Id": "3",
"PetFriendly": "False"
},
{
"Id": "4",
"PetFriendly": "False"
}
],
"Features": [
{
"WidgetId": "1",
"Name": "Easy Button",
"Type": "Button"
},
{
"WidgetId": "1",
"Name": "Lunch Lever",
"Type": "Food Service",
"MenuItems": [
"Pizza",
"Cheezburger"
]
},
{
"WidgetId": "3",
"Name": "Missles",
"Type": "Attack"
},
{
"WidgetId": "4",
"Name": "Bombs",
"Type": "Attack",
"MenuItems": [
"Rat Poison"
]
}
]
}
我尝试了很多变换但没有成功,并阅读了所有的ShiftR文档及其单元测试。一点帮助?
规格
[
{
"operation": "shift",
"spec": {
"Widgets": {
"*": {
// build the finished "Widgets" output
"Id": "Widgets[&1].Id",
"PetFriendly": "Widgets[&1].PetFriendly",
//
// Process the Features, by pushing the Id
// down into them, but maintain the same doubly
// nested structure.
// Shift works property by property, so first
// fix the properties in side each Features element,
// (pulling ID down).
// Then in a 2nd Shift can accumulate things into array.
"Features": {
"*": {
"@(2,Id)": "temp[&3].Features[&1].WidgetId",
"*": "temp[&3].Features[&1].&"
}
}
}
}
}
},
{
"operation": "shift",
"spec": {
// passthru
"Widgets": "Widgets",
"temp": {
"*": {
"Features": {
// walk thru the doubly nested structure an
// now accumulate all non-null itens into
// the the final Features array.
"*": "Features[]"
}
}
}
}
}
]
最后让它使用下面的规范,但它有一个不良的副作用:它留下空的默认数组。有没有办法删除空数组,或者在默认步骤中标记它们,以便删除它们?我检查了this GitHub issue但不确定如何将其转换为字符串数组。谁有更好的解决方案?
[
// First fill in default value for "MenuItems" since not all Features have it.
{
"operation": "default",
"spec": {
"Widgets[]": {
"*": {
"Features[]": {
"*": {
"MenuItems": []
}
}
}
}
}
},
{
// Extract the Features' properties into arrays. The defaults added above ensure that we can merge the arrays into Feature objects as in this example:
// https://github.com/bazaarvoice/jolt/blob/master/jolt-core/src/test/resources/json/shiftr/mergeParallelArrays2_and-do-not-transpose.json.
"operation": "shift",
"spec": {
"Widgets": {
"*": {
"Id": "Widgets[&1].Id",
"PetFriendly": "Widgets[&1].PetFriendly",
"Features": {
"*": {
"@(2,Id)": "temp.WidgetId",
"Name": "temp.Name",
"Type": "temp.Type",
"MenuItems": "temp.MenuItems[]"
}
}
}
}
}
},
// Finally merge the arrays into Feature objects.
{
"operation": "shift",
"spec": {
"Widgets": "Widgets",
"temp": {
"WidgetId": {
"*": "Features[&0].WidgetId"
},
"Name": {
"*": "Features[&0].Name"
},
"Type": {
"*": "Features[&0].Type"
},
"MenuItems": {
"*": "Features[&0].MenuItems"
}
}
}
}
]
结果:
{
"Widgets": [
{
"Id": "1",
"PetFriendly": "True"
},
{
"Id": "2",
"PetFriendly": "True"
},
{
"Id": "3",
"PetFriendly": "False"
},
{
"Id": "4",
"PetFriendly": "False"
}
],
"Features": [
{
"WidgetId": "1",
"Name": "Easy Button",
"Type": "Button",
"MenuItems": []
},
{
"WidgetId": "1",
"Name": "Lunch Lever",
"Type": "Food Service",
"MenuItems": [ "Pizza", "Cheezburger" ]
},
{
"WidgetId": "3",
"Name": "Missles",
"Type": "Attack",
"MenuItems": []
},
{
"WidgetId": "4",
"Name": "Bombs",
"Type": "Attack",
"MenuItems": [ "Rat Poison" ]
}
]
}