使用时
@UseInterceptors(ClassSerializerInterceptor)
就像它在文档here中解释的那样
我得到了所需的过滤结果,但是在使用mongodb时,id被格式化为_bsontype
而不是正常的string
,就像过去没有拦截器一样:
{
"id": {
"_bsontype": "ObjectID",
"id": {
"0": 92,
"1": 108,
"2": 182,
"3": 85,
"4": 185,
"5": 20,
"6": 221,
"7": 12,
"8": 56,
"9": 66,
"10": 131,
"11": 172
}
},
"createdAt": "2019-02-20T02:07:17.895Z",
"updatedAt": "2019-02-20T02:07:17.895Z",
"firstName": "The First Name",
"lastName": "The Last Name",
"email": "[email protected]"
}
如何将其转换回这样的普通id字符串?
{
"id": "5c6cb655b914dd0c384283ac",
"createdAt": "2019-02-20T02:07:17.895Z",
"updatedAt": "2019-02-20T02:07:17.895Z",
"firstName": "The First Name",
"lastName": "The Last Name",
"email": "[email protected]"
"password": "okthen"
}
你可以使用class-transformer的@Transform()
和toPlainOnly
选项:
import { Transform } from 'class-transformer';
@Entity()
export class User {
@ObjectIdColumn()
@Transform((value) => value.toString(), { toPlainOnly: true })
_id: ObjectID;
ClassSerializerInterceptor
内部使用类变换器的classToPlain()
方法。