如何将变量从引导模式传递给PHP？

Question

我想在打开模式时将data-id参数的值作为变量传递。我找到了许多与主题相关的答案，但是我是JS新手，无法实现任何解决方案。

<a data-toggle="modal" href="#showcontent" data-id="file1.html">Open1</a>
<a data-toggle="modal" href="#showcontent" data-id="file2.html">Open2</a>

<div class="modal" tabindex="-1" role="dialog">
  <div class="modal-dialog" role="document">
    <div class="modal-content">
      <div class="modal-header">
        <h5 class="modal-title">Modal title</h5>
        <button type="button" class="close" data-dismiss="modal" aria-label="Close">
          <span aria-hidden="true">&times;</span>
        </button>
      </div>
      <div class="modal-body">
        <?php echo file_get_contents($variable); ?>
      </div>
      <div class="modal-footer">
        <button type="button" class="btn btn-primary">Save changes</button>
        <button type="button" class="btn btn-secondary" data-dismiss="modal">Close</button>
      </div>
    </div>
  </div>
</div>

如何将data-id参数的值传递给我的PHP脚本？

Answer 1

由于您的提示，我找到了一个可行的解决方案：

模式：

            <div class="modal fade" id="empModal" role="dialog">
                <div class="modal-dialog">

                    <!-- Modal content-->
                    <div class="modal-content">
                        <div class="modal-header">
                          <button type="button" class="close" data-dismiss="modal">&times;</button>
                          <h4 class="modal-title">Content</h4>
                        </div>
                        <div class="modal-body">

                        </div>
                        <div class="modal-footer">
                          <button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
                        </div>
                    </div>

                </div>
            </div>

链接到模态：

                <?php 
                $id = "file1.html";
                    echo '<a data-toggle="modal" class="showfile" data-id="'.$id.'">Open</a>';
                ?>

JS：

            <script type='text/javascript'>
            $(document).ready(function(){
                $('.showfile').click(function(){
                    var fileid = $(this).data('id');
                    $.ajax({
                        url: 'ajaxfile.php',
                        type: 'post',
                        data: {fileid: fileid},
                        success: function(response){ 
                            $('.modal-body').html(response); 
                            $('#empModal').modal('show'); 
                        }
                    });
                });
            });
            </script>

和ajaxfile.php

<?php
$fileid = $_POST['fileid'];
echo file_get_contents($fileid);
exit;